All categories

3 years ago

What is the volume of a triangular pyramid with a height of 4 centimeters and a length of 6cm

Mathematics

1 answer:

yaroslaw [1]3 years ago

6 0

Considering that the length and the width are equal, the volume would be 48 cm because V=lwh/3. Hope this helped!

You might be interested in

When your income is more than your expenses, you have _____.

blagie [28]

<span>When your income is more than your expenses, y</span>ou have surplus

3 0

3 years ago

Read 2 more answers

Find the value of x A. does not exist B. -7 C. 26 D. 35

alexandr1967 [171]

Answer:

A-does not exist

Step-by-step explanation:

The pythagorian theorem :

12²+x²= (x-2)²
144+x²= x²-4x+4
144-4+x²-x²= -4x
140 = -4x
x = 140/-4
x= -35

That's absurd . A side cannot be negative since it's a distance

It was obvious from the beginning since one of the sides is greater than the hypotenus wich is impossible x≥x-2

8 0

3 years ago

Read 2 more answers

A trapezoid is broken into 2 triangles and 1 rectangle. The triangles both have a base of 2 meters and a height of 5 meters. The

Lemur [1.5K]

Answer:

Part 1) The trapezoid has an area of $20\ m^2$

Part 2) The kite has an area of $21\ m^2$

Part 3) The area of the trapezoid is less than the area of the kite

Step-by-step explanation:

Part 1

Find the area of trapezoid

we know that

The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle

$A=2[\frac{1}{2} (2)(5)]+(2)(5)$

$A=10+10=20\ m^2$

Part 2

Find the area of the kite

we know that

The area of the kite is equal to the area of two congruent triangles

$A=2[\frac{1}{2} (7)(3)]=21\ m^2$

Part 3

Compare the areas

The trapezoid has an area of $20\ m^2$

The kite has an area of $21\ m^2$

$20\ m^2< 21\ m^2$

therefore

The area of the trapezoid is less than the area of the kite

5 0

3 years ago

Read 2 more answers

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

3 years ago

And this is why I hate math.

Novosadov [1.4K]

Complementary angels add up to 90°
so x+18°=90°
so x=90-18=72°

7 0

3 years ago

Read 2 more answers