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2 years ago

Please answer this question x^2 = 11x

Mathematics

2 answers:

Masteriza [31]2 years ago

5 0

${x}^{2} = 11x \\ {x}^{2} - 11x = 0 \\ x(x - 11) = 0$

Product is equal to 0 when one of multipliers is equal to 0, so

$x = 0$

$x - 11 = 0 \\ x = 11$

Answer: x=0 or x=11

REY [17]2 years ago

3 0

Answer:

Step-by-step explanation:

x^2 = 11x

x ( x − 11 ) = 0

x = 0 (by transposing)

x − 11 = 0

x=11 (by transposing)

therefore, x= 0,11

Hope it Helps...pls Mark as Brainliest!!

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3 years ago

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3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago

over a two week period Julie had the following number of math homework problems given each day:20,0,7,10,11 0,25,15,1 find the m

kvv77 [185]

Mean: Add all the numbers and divide by the amount of numbers.

20 + 0 + 7 + 10 + 11 + 0 + 25 + 15 + 1 = 89
89/9 = 9.889 (rounded)

Mean = 9.889 (rounded)

Median: Reorder from least to greatest, and the middle number is the median.
0, 0, 1, 7, 10, 11, 15, 20, 25

The middle number is 7

Median = 7

Mode: The number that shows up the most.
Mode = 0, which shows up one time more than all the other numbers

Range: Subtract the greatest number with least number

25 - 0 = 25

Range = 25

hope this helps

3 0

3 years ago

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