Answer:
0
Explanation:
standard hydrogen is considered to be protium isotope of hydrogen that has one electron revolving around the nucleus containing one proton and no neutrons.
it's atomic number and mass number is 1
and number of neutrons = mass no. - atomic no.
= 1 - 1
=0
Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefor only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.
Answer:
5.85 moles
Explanation:
Moles in (3.52 X 10^24) molecules of water. 3.52 x 10^24 molecules x `1mol/6.02 x 10^23 molecules = 5.85 moles of H2O.
Answer:
The steps are explained below, the essential step is to find mass here, 120 g of NaOH.
Explanation:
In order to answer this question, we need to define molarity conceptually firstly to see what variables we need. According to the formula, molarity is equal to the ratio between moles and volume, while moles itself is a ratio between mass and molar mass. This means we have a formula for molarity involving mass, molar mass and volume:
In order to prepare a 500.0 mL of stock solution of 6.0 M of NaOH, we then need to find the mass of NaOH dissolved in this solution using the equation above:
Now, since we have the mass of NaOH, we can describe the steps needed to prepare this solution:
- measure 120 grams of solid NaOH;
- add this mass of NaOH into a 500.0-mL Erlenmeyer flask;
- fill approximately half of the flask with distilled water and stir gently to make sure that NaOH dissolves, if it doesn't, add more water and repeat the process;
- when NaOH fully dissolves, fill the flask to the mark.
Our solution is prepared.
