The answer is (1) CaCl2. The reaction formula of this is HCl + Ca(OH)2 = CaCl2 + H2O. This is a reaction of base and acid. So the production is CaCl2 and H2O.
Answer:
Decomposition or cracking
Explanation:
Decomposition reaction is a chemical change in which a single compound is broken down into two or more simpler products.
For example;
A → B + C
The driving force of such reaction is the high positive heat of formation of the compound which indicates that they are highly unstable.
Some stable compounds also decompose when subjected to high temperature and pressure.
Answer:
C
H²O is dissociated in water into H³O+ (hydronium ions) and OH- (hydroxide) given by;
2H²O <-----> H³O+ + OH-
If you notice initially we have 4 hydrogen atoms and 2 oxygen atoms. And similarly after the reaction we have 4 hydrogen atoms and 2 oxygen atoms.
Ratio of H to O is 4:2
or 2:1
This is very intuitive as we have 2 hydrogen atoms and 1 oxygen atom in a water molecule.
Answer: The final temperature of the system will be 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of steam = 25 g
= mass of water = 0.2384 kg = 238.4 g (1kg=1000g)
= final temperature = ?
= temperature of steam = 
= temperature of water = 
= specific heat of steam = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![25g\times 1.996J/g^0C\times (T_{final}-116)=-[238.4g\times 4.184J/g^0C\times (T_{final}-8)]](https://tex.z-dn.net/?f=25g%5Ctimes%201.996J%2Fg%5E0C%5Ctimes%20%28T_%7Bfinal%7D-116%29%3D-%5B238.4g%5Ctimes%204.184J%2Fg%5E0C%5Ctimes%20%28T_%7Bfinal%7D-8%29%5D)
Therefore, the final temperature of the system will be
We are given the complete reaction:
<span>3 H2(g) + N2(g) → 2 NH3(g)</span>
First let us convert mass to moles.
moles H2 = 5.22 kg / (2 kg/kmol) = 2.61 kmol H2
moles N2 = 31.5 kg / (28 kg/kmol) = 1.125 kmol N2
Then we find for the limiting reactant. The limiting
reactant is the one who has lower (moles/coefficient) ratio.
H2 = 2.61 / 3 = 0.87
N2 = 1.125 / 1 = 1.125
Hence the H2 is the limiting reactant so we should base
the calculation of NH3 from it. We see that 2 moles of NH3 is produced for
every 3 moles of H2, therefore:
moles NH3 = 2.61 kmol H2 * (2 kmol NH3 / 3 kmol H2) = 1.74
kmol
The molar mass of NH3 is 17 kg/kmol, therefore the mass
NH3 is:
mass NH3 = 1.74 kmol * 17 kg/kmol
<span>mass NH3 = 29.58 kg</span>
