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svp [43]
2 years ago
14

what do Mars, Mercury, and Venus have in common? A. They have a gas surface composition and a thick atmosphere. b They have many

moons and many rings. c. They have a solid rock surface composition and no rings. d. They have a thick atmosphere and many moons.
Chemistry
1 answer:
mario62 [17]2 years ago
3 0

Answer:

the best guess would have to be C

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At a certain temperature, Kc = 0.0500 and ∆H = +39.0 kJ for the reaction below, 2 MgCl2(s) + O2(g) → 2MgO(s) + Cl2(g) Calculate
Minchanka [31]

Explanation:

Since, it is shown that the reaction has been reversed. Therefore, value of K_{c} will become \frac{1}{K_{c}}.

Hence, new K_{c'} = \frac{1}{K_{c}}

                                      = \frac{1}{0.0500}

                                      = 20

Also, the number of moles of each reactant has been halved. So, K_{c''} for the reaction MgO(s) + \frac{1}{2}Cl2(g) → MgCl_{2}(s) + \frac{1}{2} O2(g) will also get halved.

Therefore,     K_{c''}  = K_{c'} = (20)^{0.5}

                               = 4.47

As the value of \Delta H is given as +39.0 kJ. So, it means that the reaction is endothermic in nature. So, energy of reactants will be more than the products. Hence, according to Le Chatelier's principle reaction will move in the forward direction.

As a result, K_{c} will also increase with increase in temperature.

6 0
3 years ago
The instruction booklet for your pressure cooker indicates that its highest setting is 11.8 psipsi . You know that standard atmo
zavuch27 [327]

<u>Answer:</u> The temperature at which the food will cook is 219.14°C

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=14.7psi\\T_1=273K\\P_2=(14.7+11.8)psi=26.5psi\\T_2=?

Putting values in above equation, we get:

\frac{14.7psi}{273K}=\frac{26.5psi}{T_2}\\\\T_2=\frac{26.5\times 273}{14.7}=492.14K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

492.14=T(^oC)+273\\\\T(^oC)=219.14^oC

Hence, the temperature at which the food will cook is 219.14°C

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3 years ago
3. A cylinder of compressed gas has a pressure of 4.882 atm on one day. The next
Debora [2.8K]

Answer:

PART A

Explanation:

3. A cylinder of compressed gas has a pressure of 4.882 atm on one day. The next

day, the same cylinder of gas has a pressure of 4.690 atm, and its temperature is

8°C. What was the temperature on the previous day in °C? Ans: 20°C.

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Help please thank you
Vikki [24]

Answer:

B I think I am pretty sure

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