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postnew [5]
4 years ago
7

the excursion boat on the river takes 2 1/2 hours to make the trip to a point 12 miles up stream and to return. If the rate at w

hich the boat travels in still water is 5 times the rate of the river current, what is the rate of the current?
Mathematics
1 answer:
MissTica4 years ago
4 0
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going 
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C

Time = distance/Rate,  (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C

Upstream time +downstream time:= 2h30 ' then:

12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
 5C = 10 and Rate of the current = 2 mi/h

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umka2103 [35]

Answer:

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Step-by-step explanation:

For this exercise you need to know that:

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In this case, you can observe in the graph of the function g(x) given in the exercise that it is an horizontal line.  Then, based on the explanation given before, you can conclude that its slope is:

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3 years ago
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Answer:

  see below

Step-by-step explanation:

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4 years ago
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frez [133]

Answer:

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Step-by-step explanation:

<u><em>The complete question is</em></u>

Segment BC is parallel to segment DE. Find the value of x

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4 years ago
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