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postnew [5]
3 years ago
7

the excursion boat on the river takes 2 1/2 hours to make the trip to a point 12 miles up stream and to return. If the rate at w

hich the boat travels in still water is 5 times the rate of the river current, what is the rate of the current?
Mathematics
1 answer:
MissTica3 years ago
4 0
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going 
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C

Time = distance/Rate,  (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C

Upstream time +downstream time:= 2h30 ' then:

12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
 5C = 10 and Rate of the current = 2 mi/h

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s344n2d4d5 [400]

Answer:

Get a calculator a graphing calculator and insert each one of those in it

4 0
2 years ago
Zack is purchasing a bag of apples. The cost of apples is proportional to the weight of the apples in pounds as shown on the gra
White raven [17]
Hello,

The graph below is the graph you may have forgotten to upload. This will help me understand the question better and to give you a great answer.

  A:  " 1 lb of apples will cost Zack $2.50. "  
___________________________________________  C:  " 4 lb of apples will cost Zack $10. "
Hope this helps


-Jurgen :D

7 0
3 years ago
Given: △ABC; AB=BC, m∠BDA = 60°, BD=4 cm, BD ⊥ BA . Find: DC, AC.
vekshin1

Answer:

DC = 10.93 cm ,  AC = 9.8 cm

Step-by-step explanation:

From trigonometry;

⇒ Tan 60 = AB/BD

⇒AB = BD Tan 60 ( where BD = 4 cm )

⇒ AB = 6.93 cm

Also, AB=BC , therefore;

⇒ BC = 6.93 cm

⇒ Cos 60 = BD/AD

⇒ AD = BD/ Cos 60 = 4/Cos 60

⇒ AD = 8 cm

From Pythagoras theorem;

⇒ AC^{2} = AB^{2} + BC^{2} = (6.93)^{2} + (6.93)^{2}

⇒ AC = \sqrt{96.05} = 9.80 cm

⇒ DC = BD + BC = 4 + 6.93

⇒ DC = 10.93 cm

8 0
2 years ago
Please help me with question 26
AleksAgata [21]
Answer: B) 65 degrees

-----------------------------------------------------

angle AEB = angle GEC
5x = 3x+10
5x-3x = 10
2x = 10
x = 5

angle GEC = 3x+10
angle GEC = 3*5+10
angle GEC = 25 degrees

Angle FEG = 90 - (angle GEC)
Angle FEG = 90 - 25
Angle FEG = 65 degrees

5 0
3 years ago
How do you write 5 out of 6 in a fraction. Show how you got the answer.
antiseptic1488 [7]

Answer:

5/6

Step-by-step explanation:

bro ok this it ok okik

6 0
2 years ago
Read 2 more answers
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