Janet invested $6000 at 2 %.
Let <em>x</em> = amount invested at 2 %. Then 10 000 - <em>x</em> = amount invested at 12 %
interest at 2 % + interest at 12 % = 600
0.02<em>x</em> + 0.12(10 000 –<em> x</em>) = 600
0.02<em>x</em> + 1200 – 0.12<em>x</em> = 600
0.10<em>x</em> = 600
x = 600/0.10 = 6000
Answer:
only D
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Answer:
c
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Answer:
i honestly dont know its tooooo hard
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