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2 years ago

if the second term of a geometric series is 48 and its fifth term is 6 then find the sum of its first term 6 terms

Mathematics

1 answer:

aev [14]2 years ago

6 0

Answer:

The answer is 189.

Step-by-step explanation:

This geometric sequence is actually just a division of 2 for every term downwards. Therefore, we can see the first term is $48 \cdot 2$ which is 96. Hence, we can work our way down from there:

List:

First term: 96

Second term: 48

Third term: 24

Fourth term: 12

Fifth term: 6

Sixth term: 3

Now, all we have to do is to add all the first 6 terms together to get:

$96 + 48 + 24 + 12 + 6 + 3$

$= 189$

The answer is 189.

Hope this helped!

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Answer:

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Step-by-step explanation:

Given

Tonya

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Leo

$x \to g(x)$

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$4 \to 470$

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The initial value is when x = 0. So, we have:

$f(x) = 490 * 0.88^x$

$f(0) = 490 * 0.88^0$

$f(0) = 490 * 1$

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From Leo's table

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By comparison;

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An exponential function is:

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$(x_2,y_2) = (2,360)$

So, the equation becomes:

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Solving $480 = ab^0$ , we have:

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$480 = a$

$a= 480$

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$360 = 480 * b^2$

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Take square roots

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$b=0.87$ -- Leo's rate

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2 years ago

if the second term of a geometric series is 48 and its fifth term is 6 then find the sum of its first term 6 terms​

if the second term of a geometric series is 48 and its fifth term is 6 then find the sum of its first term 6 terms