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Degger [83]
3 years ago
11

What is the solution set of the equation?

title="\sqrt{x} -18+9x=x" alt="\sqrt{x} -18+9x=x" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0

9514 1404 393

Answer:

  x ∈ {2.07014981016}

Step-by-step explanation:

The equation can be rewritten as ...

  √x = 18-8x

  x = 324 -288x +64x²

  64x² -289x +324 = 0

  x = (289 ±√577)/128 ≈ {2.07015, 2.44548}

Since √x must be positive, we know that ...

  18 -8x ≥ 0

  x ≤ 18/8 = 2.25

The larger of the above solutions is extraneous, so the solution set is ...

  x ∈ {(289 -√577)/128} ≈ {2.07015}

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Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

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<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

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