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Varvara68 [4.7K]
3 years ago
14

PLEASE GO TO THIS QUESTION QUICKLY

Physics
1 answer:
bazaltina [42]3 years ago
7 0
What how do i get there
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Seeing a police officer ahead and not being sure of the speed limit, a driver slows from 65 mi/hr to 55 mi/hr in 4.0 seconds, tr
Flauer [41]

Answer:

-1.13 m/s^2

Explanation:

The acceleration of the car is given by:

a=\frac{v-u}{t}

where

v is the  final velocity

u is the initial velocity

t is the time

Here we have to convert the velocities from mi/hr to m/s. Keeping in mind that

1 mi = 1609 m

1 h = 3600 s

We get:

u = 65 mi/h \cdot \frac{1609}{3600}=29.1 m/s\\v = 55 mi/h \cdot \frac{1609}{3600}=24.6 m/s

While the time interval is

t = 4.0 s

Substituting,

a=\frac{24.6 - 29.1}{4.0}=-1.13 m/s^2

3 0
3 years ago
Bohr's model of the atom included a positively charged _____ orbited by negatively charged _____. nucleus, protons nucleus, elec
alexgriva [62]
Electrons and neutrons


altho if I were you id check other sites. Hopefully I was able to help.. Have a great day :)
7 0
4 years ago
Read 2 more answers
Who discovered that sunlight is made of all the colors of the rainbow?
adelina 88 [10]
Isaac Newton was experimenting with prisms and discovered that all light is made up of the colors of the rainbow.

The correct answer is A.
6 0
3 years ago
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Which of these is heated up the least by the sun's energy?
NeX [460]
Soil.............................
7 0
4 years ago
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n alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 5.94 cm in a uniform magnetic field with B = 1.10 T.
9966 [12]

Answer:

a). V = 3.13*10⁶ m/s

b). T = 1.19*10^-7s

c). K.E = 2.04*10⁵

d). V = 1.02*10⁵V

Explanation:

q = +2e

M = 4.0u

r = 5.94cm = 0.0594m

B = 1.10T

1u = 1.67 * 10^-27kg

M = 4.0 * 1.67*10^-27 = 6.68*10^-27kg

a). Centripetal force = magnetic force

Mv / r = qB

V = qBr / m

V = [(2 * 1.60*10^-19) * 1.10 * 0.0594] / 6.68*10^-27

V = 2.09088 * 10^-20 / 6.68 * 10^-27

V = 3.13*10⁶ m/s

b). Period of revolution.

T = 2Πr / v

T = (2*π*0.0594) / 3.13*10⁶

T = 1.19*10⁻⁷s

c). kinetic energy = ½mv²

K.E = ½ * 6.68*10^-27 * (3.13*10⁶)²

K.E = 3.27*10^-14J

1ev = 1.60*10^-19J

xeV = 3.27*10^-14J

X = 2.04*10⁵eV

K.E = 2.04*10⁵eV

d). K.E = qV

V = K / q

V = 2.04*10⁵ / (2eV).....2e-

V = 1.02*10⁵V

7 0
3 years ago
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