The formula for maximum distance is
X = (V^2 / g) * sin (2 * theta)
10 = (V^2 / 9.8) * sin (2 * 20)
10 = (V^2 / 9.0) * sin(40)
10 = (V^2 / 9.8) * 0.324
v^2 = (10 / 0.324) * 9.8
V^2 = 302.47
v = 17.39 meters/sec (takeoff speed)
The horizontal speed is = Takeoff Speed * Cos(20) = 17.39 * 0.910 = 16.341 meters / sec
Answer:
a) 0.09N b) positive x direction
Explanation:
Force on a conductor carrying current in a magnetic field can be expressed as;
F = BILsin(theta) where
F is the force on the conductor (wire)
B is the uniform magnetic field I'm Tesla = 1.8Tesla
I is the current in the wire = 5×10^-2A
L is the length of the wire = 1m
theta is the angle that the conductor make with the magnetic field = 90° (since the wire in the horizontal direction is perpendicular to the field acting upwards)
Substituting this value in the formula to get F we have;
F = 1.8×5×10^-2×1 × sin90°
F = 0.09N
The force on the wire is 0.09N
b) The direction of the force is in the positive x direction since the wire acts horizontally to the magnetic field.
Answer:
a) ΔV = 20 V
, b) Q = 35.4 10⁻⁹ C, c) C = 1.77 10⁻⁹ F
Explanation:
a) The electric potential is
ΔV = E x
ΔV = 4.0 10⁵ 50 10⁻⁶
ΔV = 20 V
c) The capacity of a capacitor is
C = ε₀ A / d
The area of a square plate is
A = L²
A = 0.10²
A = 0.01 m²
L = 50mm = 50 10⁻⁶ m
Let's calculate
C = 8.85 10⁻¹² 0.01 /50 10⁻⁶
C = 1.77 10⁻⁹ F
b) the charge is
Q = C ΔV
Q = 1.77 10⁻⁹ 20
Q = 35.4 10⁻⁹ C
Answer:
nine
nine is the atomic number of fluorine
Answer:
Young's modulus for the rope material is 20.8 MPa.
Explanation:
The Young's modulus is given by:
Where:
F: is the force applied on the wire
L₀: is the initial length of the wire = 3.1 m
A: is the cross-section area of the wire
ΔL: is the change in the length = 0.17 m
The cross-section area of the wire is given by the area of a circle:
Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:
Where:
: is the tension of the wire
: is the weigh of the object = mg
m: is the mass of the object = 1700 kg
g: is the acceleration due to gravity = 9.81 m/s²
Hence, the Young's modulus is:
Therefore, Young's modulus for the rope material is 20.8 MPa.
I hope it helps you!
