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lara [203]
3 years ago
11

A magnetic field is passing through a loop of wire whose area is 0.020 m2. The direction of the magnetic field is parallel to th

e normal to the loop, and the magnitude of the field is increasing at the rate of 0.24 T/s. (a) Determine the magnitude of the emf induced in the loop. (b) Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in m^2/s) should the area be changed at the instant when B = 2.1 T if the induced emf is to be zero? Use a minus sign if the area is to be shrunk
Physics
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer:

a) E = 0.0048 Volts

b)  dA/dt = - 0.002285 m²/s

Explanation:

Given:

Area, A = 0.020 m²

Rate of change of magnetic field, dB/dt = 0.24 T/s

a) The magnitude of the emf induced (E) is given as:

  E= A × (dB/dt)

  on substituting the values in the above equation, we get

E = (0.020 m²) × (0.24 T/s)

or

E = 0.0048 Volts

b) Now, The induced emf when both the area and the magnetic field is varying

we have

E = B(dA/dt) + A(dB/dt)

Now, for the given case induced emf is zero i.e E = 0 and magnetic field B = 2.1 T

thus,

0 = (2.1 T)(dA/dt) + (0.020 m2)(0.24 T/s)

dA/dt = - 0.002285 m²/s

Hence, the area should be decreased at the rate of 0.002285 m²/s

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The solution for this problem is:
Let u denote speed. 

Equating momentum before and after collision: 
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= 1.6 m / s is the answer for this question. This is the speed after the collision.
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3 years ago
A tuning fork generates sound waves with a frequency of 240 Hz. The waves travel in opposite directions along a hallway, are ref
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Answer:

The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.

Explanation:

Given that,

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Distance of fork = 14 .0 m

We need to calculate the path difference

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\Delta x=2(L_{2}-L_{1})

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\Delta x =2((46.0-14.0)-14.0)

\Delta x=36\ m

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Put the value into the formula

\lambda=\dfrac{343}{240}

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We need to calculate the phase difference

Using formula of the phase difference

\phi=\dfrac{2\pi}{\lambda}\times \delta x

Put the value into the formula

\phi=\dfrac{2\pi}{1.42}\times36

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Hence, The phase difference between the reflected waves when they meet at the tuning fork is 159.29 rad.

7 0
3 years ago
9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
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Answer:

2.61 atm

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Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

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V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

4 0
2 years ago
elastic wire extend by 1.ocm when a load on 20g range from It, what additional load will it be required Cause the futher extensi
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Answer:

40g

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A cylinder which is in a horizontal position contains an unknown noble gas at 4.63 × 104 Pa and is sealed with a massless piston
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Answer:

The change in internal energy of the system is -17746.78 J

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Hence, The change in internal energy of the system is -17746.78 J

3 0
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