If the third term in an arithmetic sequence is 7 and the common difference is -5, what is the value of the fourth term?

Mathematics

2 answers:

kozerog [31]3 years ago

8 0

Answer: 2

Step-by-step explanation:

I hope this helps!!!

tatiyna3 years ago

4 0

The answer is 2. If the difference is -5, all you have to do is subtract 5 from 7, since 7 is the third term and the question is asking for the fourth term.

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ANSWER QUICK !!

Nonamiya [84]

507 - 30 = 477

477 / 0.4 = 1192.5

1192.4 / 8 = 149.0625 miles or 150 miles

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7 0

3 years ago

Please help! Thankss!! :)

Vsevolod [243]

Answer:

Step-by-step explanation:

If b = -4, then -4(-4) is 16, since 2 negatives is a positive when multiplying or dividing. Then add 16 and 5, since 5 is c. You'll get 21

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2 years ago

Read 2 more answers

1. Derive this identity from the sum and difference formulas for cosine:

barxatty [35]

$\bf \begin{cases}
cos({{ a}} + {{ b}})= cos({{ a}})cos({{ b}})- sin({{ a}})sin({{ b}})\\\\
cos({{ a}} + {{ b}})+sin({{ a}})sin({{ b}})=\boxed{cos({{ a}})cos({{ b}})}\\\\
--------------------\\\\
cos({{ a}} - {{ b}})= cos({{ a}})cos({{ b}}) + sin({{ a}})sin({{ b}})\\\\
cos({{ a}} - {{ b}})-sin({{ a}})sin({{ b}})=\boxed{cos({{ a}})cos({{ b}})}
\end{cases}\\\\
-----------------------------\\\\$

$\bf cos(a)cos(b)=cos(a)cos(b)\qquad thus
\\\\\\
cos({{ a}} + {{ b}})+sin({{ a}})sin({{ b}})=cos({{ a}} - {{ b}})-sin({{ a}})sin({{ b}})
\\\\\\
sin({{ a}})sin({{ b}})+sin({{ a}})sin({{ b}})=cos({{ a}} - {{ b}})-cos({{ a}} + {{ b}})
\\\\\\
2sin({{ a}})sin({{ b}})=cos({{ a}} - {{ b}})-cos({{ a}} + {{ b}})
\\\\\\
sin({{ a}})sin({{ b}})=\cfrac{cos({{ a}} - {{ b}})-cos({{ a}} + {{ b}})}{2}
\\\\\\
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goblinko [34]

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Step-by-step explanation:

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3 years ago