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myrzilka [38]
3 years ago
11

Which of the following techniques can you not use to make the members of the std namespace available to your code? a. Code a usi

ng directive for the namespace b. Code an include preprocessor directives for the members c. Identify the members using fully qualified names d. Code a using declaration for each member
Computers and Technology
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer:

b. Code an include preprocessor directives for the members

Explanation:

Namespace in programming can be defined as the declarative region which provides scope for the identifiers such as the functions, name of the types, variables, etc.

The namespaces are $\text{used to organize}$ the code into the logical groups and also used to prevent the name collision.

The ways that can be used outside the namespace $\text{can access the members}$ as :

-- the code used the fully qualifies name

-- by using the declaration to bring one of the identifier into the scope

-- by using the directive to bring all the things in the newspaper into the scope.

Thus the correct option is (b).

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Burka [1]
I would say it has to be b but its what the correct answer is its up to you!

I hoped this helped you out!

Have a nice day!

4 0
3 years ago
Hide Time Remaining A
Maslowich

Answer:

True

Explanation:

The class Math include mathematical functions such as sin(), cos(), tan(), abs(), etc

If the given statement is not written, each of the math function will be written as (take for instance, the sin() function):

<em>Math.sin()</em>

<em></em>

But after the statement has been written (it implies that the Math library has been imported into the program) and as such each of the mathematical function can be used directly.

So instead of <em>Math.sin(), </em>you write <em>sin()</em>

5 0
3 years ago
no one can succeed in his or her career without relying on others for help or opportunities. It’s best, though,
fenix001 [56]

idk good luck man idek if this is a question but if it is just go with c or b

3 0
3 years ago
Which of the following class definition defines a legal abstract class Group of answer choices public class Rectangle abstract {
valkas [14]
<h2>Question</h2>

Which of the following class definition defines a legal abstract class Group of answer choices

(a)

public class Rectangle abstract {

   public abstract double findArea ( );

   

}

(b)

public abstract class Rectangle {

   public abstract double findArea ( );

   

}

(c)

public class Rectangle {

   public abstract double findArea ( );

   

}

(d)

public class abstract Rectangle {

   public abstract double findArea ( );

   

}

<h2>Answer:</h2>

(b)

public abstract class Rectangle {

   public abstract double findArea ( );

}

<h2>Explanation:</h2>

When a class is declared with the abstract keyword, the class is called an abstract class. Abstract classes cannot be instantiated and may include one or more abstract methods. If a class contains an abstract method, then it (the class) must be declared abstract.

In Java, abstract classes are defined using the following format:

<em>[access_modifier]</em> abstract class <em>[name_of_class]</em>

[access_modifier] specifies the access modifier of the class which could be public, private, e.t.c

abstract is the keyword that specifies that the class is an abstract class.

class is a keyword used for defining classes

name_of_class specifies the name of the class.

The only option that fulfils this format is <em>option b</em> where;

(i) The access modifier is public

(ii) The name of the class is Rectangle

Option a is not correct because the <em>abstract</em> keyword is supposed to come before the <em>class</em> keyword.

Option c is not correct because the keyword <em>abstract</em> is missing. In other words, the class must be declared abstract since it contains abstract method findArea();

Option d is not correct because the <em>abstract</em> keyword is supposed to come before the <em>class</em> keyword.

7 0
3 years ago
How to make a water bottle rocket??
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6 0
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