Question

Factor and find the zeros k^2+7k+12

Answer 1

Answer:

(k+3)(k+4)

The zeros are -3 and -4

Step-by-step explanation:

k2+7k+12

The middle number is 7 and the last number is 12.

This means we need two numbers that:

Add together to get 7

Multiply together to get 12

to fit in this equation (k+_)(k+_)

in this equation, it would be 3 and 4

3+4 = 7

3*4 = 12

Now we fill in the blanks to get

(k+3)(k+4)

To get the zeros, use the equations

k+3=0 and k+4=0

You end up with

k=-3 and k=-4