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HACTEHA [7]
2 years ago
8

What is (-3 3/4) - (2 1/4)?

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
3 0

Answer: -6

Step-by-step explanation:

Rewrite the expression:

-3\frac{3}{4}-2\frac{1}{4}

Factor out the negative:

-3\frac{3}{4}-2\frac{1}{4}

-(3\frac{3}{4} +2\frac{1}{4})

Rewrite the sum:

-(3\frac{3}{4} +2\frac{1}{4})

-((3+2)+(\frac{3}{4}+\frac{1}{4}))

Calculate the sum:

-((3+2)+(\frac{3}{4}+\frac{1}{4}))

-(5+1)

Solve:

-(5+1)

-6

Please mark brainliest if this helped you :)

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poizon [28]
Constant of proportionality is 4

equation: x/y = 4

explanation:
let's take 20 and 5 for example, if you divide 20 by 5, you will 4 of course. that's the proportionality for the first one. if you continue to divide x value by y value you will get 4. for the last two you would divide 28 by 4 and multiply 8 by 4.
5 0
2 years ago
Read 2 more answers
The range of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is Your answer: {−1, 1, 3} {−1, −1, 1, 3} {−4, −2, 2,
nalin [4]

Answer:

The range is all the y values.

Therefore, the range is : {-4,-2,2}.....I realize choice c has all the y values listed, however, if u have repeating y values, u only have to list it once.

Step-by-step explanation:

6 0
3 years ago
A disease has a constant force of mortality, µ. Historically 10% of all people with the disease die within 20 years. A more viru
kolbaska11 [484]

Answer:

Step-by-step explanation:

For the disease having force of mortality  µ.

we apply exponential distribution law

probability of dying within 20 years

p( x <20) = 1-e^{-\mu} = .1

e^{-\mu} = .9

For the disease having force of mortality  2µ.

we apply exponential distribution law

probability of dying within 20 years

p( x <20) = 1 - e^{-2\mu}

= 1 - ( .9)²

= 1 - .81

= .19

or 19%

5 0
3 years ago
The ratio of teachers needs to be 1:30. If there were 120 students, how many teachers would be needed?
mezya [45]

Answer:

4:120

Step-by-step explanation:

for 120 student they would be 4 teacher needed per 30 student

4:120

4 0
3 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
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