Answer:
A) A very thin atmosphere and temperatures vary from 427 degrees to -180 degrees Celsius (800 to -292 degrees Fahrenheit)
Explanation:
I did this quiz and this was the answer.
Answer:
The new volume of the gas is decreased, to 0.329 L
Explanation:
Step 1: Data given
Volume of oxygen = 500 mL = 0.500 L
Pressure = 1.3 atm
Temperature = 25.0 °C
Temperature increases to 29.0 °C
New pressure = 2.0 atm
Step 2: Calculate new volume
p1*V1/T1 = p2*V2/T2
⇒with p1 = the initial pressure = 1.3 atm
⇒with V1 = the initial volume = 0.500L
⇒with T1 = the initial temperature = 25 °C = 298 K
⇒with p2 = the new pressure = 2.0 atm
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the new temperature = 29 °C = 302 K
(1.3 * 0.500)/298 = (2.0 * V2) /302
0.0021812 = 2.0V2 / 302
V2 = 0.329 L = 329 mL
The new volume of the gas is decreased, to 0.329 L
5 types of air pollution would include: Carbon Monoxide, Lead, Nitrogen oxides, sulfur oxides. I only know those 4 actually… hope it helped
A) 0 because Fe is uncharged
b) 0 because O in O2 is uncharged as well
c) +3 because each Fe atom lost 3 electrons
d) -2 because each oxygen aim gained 2 elections
1 mole ------------- 6.02 x 10²³ atoms
( moles Cu) ------- 1.48 x 10²⁵ atoms
moles Cu = ( 1.48 x 10²⁵ ) x 1 / 6.02 x 10²³
moles Cu = 1.48 x 10²⁵ / 6.02 x 10²³
=<span> 24.58 moles of Cu</span>
<span>hope this helps!</span>
