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3 years ago

The specific gravity of H2SO4 is 1.84, its density would be?

Chemistry

1 answer:

Vika [28.1K]3 years ago

4 0

The density would be 1.84 g/cm<span>³</span>

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The measure of a right angle is

yawa3891 [41]

Answer:

90° is the measure, hope this helped :)

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2 years ago

Relate what you've learned about the cell to how we inherit traits from our parents. Include the following vocab words, : nucleu

Veronika [31]

Meiosis makes sperm cells and eggs in our parents.
Genes are passed on from them to us.
As Genes carry characteristic, we inherit some characters of our either parent.
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When, it translated, it forms into "Protein"

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Hope this helps!

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3 years ago

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Im about to take first year chemistry for engineering. Should i review or will this be done in class? If yes what are some conce

sashaice [31]

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3 years ago

How many grams of S are in 475 g of SO2?

enot [183]

There are 237. 5 g of Sulfur,S in 475 g of SO2?

<h3 />

<h3>Calculation of grams of Sulfur</h3>

From the question, we can say that

The molar mass of sulfur = 32 g/mol

The molar mass of oxygen = 16 g/mol

Therefore,

The molar mass for SO2 = 32 + (16 × 2) g/mol = 64 g/mol

Now,

If 1 mole of SO2 contains 1 mole of S

Then 64 g of SO2, will contain 32g of S;

Such that

475 g of SO2 will give { $\frac{ 32g of S) ( 475 g of SO2)}{64 of SO2}$ } = 237. 5 g of Sulfur.

Learn more about molar mass here :brainly.com/question/18291695

6 0

2 years ago

Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode

mylen [45]

Answer:

696 h

Explanation:

Let's consider the reduction of Cr³⁺.

Cr³⁺(aq) + 3e⁻ → Cr(s)

We can establish the following relations.

The molar mass of Cr is 52.0 g/mol.
1 mol of Cr is deposited when 3 moles of e⁻ circulate.
1 mole of e⁻ has a charge of 96468 c (Faraday's constant).
1 A = 1 c/s
1 h = 3600 s

<em>How many hours will it take to plate 13.5 kg of chromium onto the cathode if the current passed through the cell is held constant at 30.0 A?</em>

$13.5 \times 10^{3} gCr.\frac{1molCr}{52.0gCr} .\frac{3mol/e^{-} }{1molCr} .\frac{96468c}{1mol/e^{-}} .\frac{1s}{30.0c} .\frac{1h}{3600s} =696 h$

3 0

3 years ago