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iren [92.7K]
3 years ago
8

Which combination of elements below will bond ionically and in the same ratio as lithium when it bonds to sulfur?

Chemistry
2 answers:
satela [25.4K]3 years ago
7 0
Lithium sulfide (Li2S) would have 2 lithium atoms for every sulfur atom and would form an ionic bond. Sodium oxide (Na2O) has 2 sodium atoms for every oxygen atom (same ratio) and forms an ionic bond.
kupik [55]3 years ago
6 0

B. Sodium and Oxygen

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There's 6.022×10^23 particles in 1 mole of anything

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Water can be formed in the following reaction: 2H2 + O2 —> 2H2O. If you have 12 moles of Hydrogen gas (H2), how many moles of
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Explanation:

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Determine whether you can swim in 1.00 x 10^27 molecules of water.​
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We can not swim in 1.00 × 10²⁷ molecules of water

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The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

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?? no entiendo la pregunta?...pero gracias por los puntos free UvU

Explanation:

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