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3 years ago

(NO LINKS)!~Brainliest IF YOU CAN SIMPLIFY AND SOLVE FOR THE UNKNOWN~!(3 + 5)² + [8 - 11] + Z = 4(Z - 2)

Mathematics

1 answer:

OleMash [197]3 years ago

7 0

Answer:

(3+5) = 8 times 8 = 64 64+(8-11)+Z=64+(-3) + Z=62+z= 62+2 = 64

Step-by-step explanation:

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2.) Use the Slope Intercept Form of a line to find the equation of the line from point C to point D.

mezya [45]

First we need slope

C=(0,0)
D(7,12)

$\\ \sf\longmapsto m=\dfrac{12-0}{7-0}$

$\\ \sf\longmapsto m=\dfrac{12}{7}$

Put D co-ordinates on y=mx+b

$\\ \sf\longmapsto 12=\dfrac{12}{7}(7)+b$

$\\ \sf\longmapsto 12=12+b$

$\\ \sf\longmapsto b=12-12$

$\\ \sf\longmapsto b=0$

Now

slope intercept form.

$\\ \sf\longmapsto y=\dfrac{12}{7}x$

As b=0

8 0

2 years ago

Read 2 more answers

Please help i need to write out my work to so please tell me how to show it

Anarel [89]

For the first one write 9 divided by 2 gives your your radius an it’s 3.5. the formula is 2 x 3.14 x radius and that gives you 21.98.

the 2nd one is 2 x 3.14 x 9 = 56.52

the 3rd is 2 x 3.14 x 5= 31.4

formula is always 2 x 3.14 (or pie) x radius

to get your radius from your diameter you do your diameter divided by 2

3 0

1 year ago

Read 2 more answers

URGENT: Click on the graph to choose the correct answer to the equation.

FrozenT [24]

Answer:

The first graph.

Step-by-step explanation:

The equation is x is greater than 2. Therefore, the graph needs to shade anything greater than 2, but not 2.

4 0

3 years ago

Al trazar en el plano cartesiano el angulo a cuyo lado terminal es el punto de ( 3,4). Los valores de las funciones del coseno y

Igoryamba

Answer:

$cos(\alpha)=\frac{3}{5}=0.6$

$cosec(\alpha)=\frac{5}{4}=1.25$

Step-by-step explanation:

El cos(α) se define como el cociente entre el cateto adyacente y la hipotenusa.

El valor del cateto adyacente en nuestgro caso es CA = 3.

La hipotenusa se calcual de la siguiente manera:

$h=\sqrt{3^2+4^2}=5$

Por lo tanto, el cos(α) sera:

$cos(\alpha)=\frac{3}{5}=0.6$

El cosec(α)=h/CO.

El cateto opuesto CO = 4 y la hipotenusa h = 5

Por lo tanto, el cosec(α) sera:

$cosec(\alpha)=\frac{5}{4}=1.25$

Espero te haya sido de ayuda!

4 0

3 years ago

Write an equation in point-slope form of the line that passes through the given point and has the given slope. (3,5);m=-1

KIM [24]

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=-1(x-3) \\\\\\ y-5=-x+3\implies y=-x+8$

3 0

3 years ago