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Artemon [7]
3 years ago
7

jo goes to a restaurant for a meal. there are 5 starters and 7 main courses to choose from. Jo chooses a starter and a main cour

se how many possible combinations could she order?
Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0

Answer:

35 combinations of a starter and a main course.

Step-by-step explanation:

1a, 1b, 1c, 1d, 1e, 1f, 1g

2a, 2b, 2c, 2d, 2e, 2f, 2g

3a, 3b, 3c, 3d, 3e, 3f, 3g

4a, 4b, 4c, 4d, 4e, 4f, 4g

5a, 5b, 5c, 5d, 5e, 5f, 5g

i hope this helps

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The area of a rectangular wall of a barn is 85 square feet. Its length is 12 feet longer than the width. Find the length and wid
MaRussiya [10]

Answer:

Length = 17 feet, Width = 5 feet

Step-by-step explanation:

Given:

The area of a rectangular wall of a barn is 85 square feet.

Its length is 12 feet longer than the width.

Question asked:

Find the length and width of the wall of the barn.

Solution:

Let width of a rectangular wall of a barn = x

<u>As length is 12 feet longer than the width.</u>

Length of a rectangular wall of a barn = 12+x

As we know:

Area\ of\ rectangle=length\times breadth

85=(12+x)x\\\\85=12x+x^{2} \\

Subtracting both sides by 85

x^{2} +12x-85=0\\x^{2} +17x-5x-85=0\\Taking\ common\\x+(x+17)-5x(x+17)=0\\(x+17)(x-5)=0\\x+17=0, x-5=0\\x=-17,x=5

As width can never be in negative, hence  width of a rectangular wall of a barn = x = 5 feet

Length of a rectangular wall of a barn = 12+x=12+5=17\ feet

Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.

                 

4 0
3 years ago
PLEASE HELP. <br> I know how to do these but I'm stuck on this one.
Nezavi [6.7K]

Steve ran 11 miles

let the distance Steve ran be x

Then distance Kevin ran is x + 4 ( 4 miles more than Steve )

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2x + 4 = 26 ( subtract 4 from both sides )

2x = 22 ( divide both sides by 2 )

x = 11

Steve ran 11 mies and Kevin ran 11 + 4 = 15 miles

check 11 + 15 = 26


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