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iogann1982 [59]
3 years ago
8

Explain

Physics
1 answer:
fenix001 [56]3 years ago
7 0

Answer and Explanation:

--> MRI (Magnetic Resonance Imaging) is an imaging technique that involves the use of radio waves and magnetic field to generate high detailed images of the human body. It's clinical applications includes:

• Bone and joint MRI:  these are done to check for bone and joint problems such as bone marrow disorders, arthritis, or bone tumours.

• A Spine MRI: This is used to investigate the spinal disc and innervations for disorders such as spinal tumours.

• Chest MRI: This is used to detect abnormalities of the heart, heart valves and coronary arteries.

--> X-RAY: These are electromagnetic waves of short wavelength with high penetrating power. They are produced when fast moving electrons strike a mass of heavy atoms such as those of metals. It's applications includes:

• They are used to detect hidden cracks in materials.

• They are used to show broken bones in human body.

• They are used in the study of internal structures of crystals.

• In agriculture, x-rays are used in killing germs.

--> ULTRASOUND: This makes use of high frequency sounds to detect abnormalities in the human body. An ultrasound machine transmits sound waves into the body which are reflected at the surfaces between the tissues of different density. It can also be used in different disciplines such as imaging, cleaning, mixing, navigation and communication   It's applications includes:

•. Detection of Cracks: when applied on metallic surface under investigation, high frequency sound wave reflects back which and be predicted and recorded.

--> INFRARED RADIATION: This is a type of electromagnetic radiation with wavelength longer than visible light. It is visible to the human eye and most heated surfaces transmits infrared radiation. It's applications includes:

• it is used for the purpose of sensing and detection. For example the night vision goggles and infrared cameras. Remote control makes use of infrared light waves to change channels in the television.

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An air-track glider attached to a spring oscillates between the 10 cm mark and the 60 cm mark on the track. The glider completes
Assoli18 [71]

Answer:

a) Time period is 3.3 seconds

b) The frequency is 0.3030 Hz

c) amplitude is 0.25 m

d) maximum speed is 0.476 m/s

Explanation:

Given the data in the question;

a) Period

Time Period T = Time taken for one oscillation

T = 33s / 10 = 3.3 seconds

Therefore, Time period is 3.3 seconds

b) Frequency

we know that frequency is the inverse of time period

so;

Frequency f = 1/T = 1 / 3.3 s

Frequency f = 0.3030 Hz

Therefore, The frequency is 0.3030 Hz

c) amplitude

amplitude A = \frac{1}{2}( 60 cm - 10 cm )

A = \frac{1}{2} × 50 cm

A = 25 cm

A = 0.25 m

Therefore, amplitude is 0.25 m

d) maximum speed of the glider

maximum speed V_{max} = ωA

and ω = 2π/T

so maximum speed V_{max} = \frac{2\pi }{T}A

so we substitute

so maximum speed V_{max} = \frac{2\pi }{3.3} × 0.25 m

so maximum speed V_{max} = 0.476 m/s

Therefore, maximum speed is 0.476 m/s

5 0
2 years ago
Electromagnetic induction is the production of a voltage across a conductor when it is exposed to a varying magnetic field. This
Darina [25.2K]

Answer:

D) Electric power distribution.

Explanation:

Electric power distribution requires high voltages to efficiently transmit electric power. This requires use of a transformer which uses electromagnetic induction.

6 0
3 years ago
Read 2 more answers
A 50.0 kg woman climbs a flight of stairs 6.00 m high in 15.0 s. How much power does she use.
WITCHER [35]

Her weight = (mass) · (gravity) = (50kg) · (9.8 m/s²)

Work = (weight) · (height) = (50kg) · (9.8 m/s²) · (6 m)

Power = (work) / (time) = (50kg) · (9.8 m/s²) · (6 m) / (15 s)

Power = (50 · 9.8 · 6 / 15) · (kg · m² / s³)

Power = 196 (kg · m / s²) · (m) / s

Power = 196 Newton-meter/second

<em>Power = 196 watts</em>

6 0
3 years ago
In a lab, a student drags a shoe across the floor at constant speed. If the coefficient of static friction between the floor and
Svetllana [295]
<span>B) 0.6 N
   I suspect you have a minor error in your question. Claiming a coefficient of static friction of 0.30N is nonsensical. Putting the Newton there is incorrect. The figure of 0.25 for the coefficient of kinetic friction looks OK. So with that correction in mind, let's solve the problem. The coefficient of static friction is the multiplier to apply to the normal force in order to start the object moving. And the coefficient of kinetic friction (which is usually smaller than the coefficient of static friction) is the multiplied to the normal force in order to keep the object moving. You've been given a normal force of 2N, so you need to multiply the coefficient of static friction by that in order to get the amount of force it takes to start the shoe moving. So: 0.30 * 2N = 0.6N And if you look at your options, you'll see that option "B" matches exactly.</span>
7 0
3 years ago
Read 2 more answers
Which of the following is the best example of uniform circular motion? A. A child riding on a constantly spinning merry-go-round
Ulleksa [173]

A. because as the merry-go-round spins the child accelerates towards the center of the merry-go-round at a uniform rate.

5 0
3 years ago
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