Answer:
Rachel needs 0.52 kg of fertilizer.
Explanation:
Since the surface is a <em>square</em> of 10 ft of size its area is A = 10 ft x 10 ft = 1.0 x 10² ft². <em>One third</em> of that space is devoted to tomatoes (<em>"space is divided equally among tomatoes, lettuce, and strawberries"</em>), that is, 1/3 x 100 ft² = 33 ft².
We calculate the kilograms of fertilizer required we need to know 2 equivalences:
1 ac = 43,560 ft²
1 lb = 0.4535 kg
Then, we can use proportions to find out the amount of fertilizer used:
Answer:
they must do a background check
Explanation:
they need to check the liscence and do a small interrigaition
Answer:
hot air rises because gases expand as they heat up.When air heats up and expands,its density also increases.The warmer,less dense air effectively floats on top of the colder, dense air below it. This creates a buoyant force that causes warmer air to rise.
cold air sinks because it is heavier as its more dense ( because of closely packed molecules) soits harder for them to move and they absorb less energy. Also, gravity pulls on it more strongly.
Hope it helps :)
Answer:
Na₃PO₄ + 3HCl —> 3NaCl + H₃PO₄
The coefficients are: 1, 3, 3, 1
Explanation:
_Na₃PO₄ + __HCl —> __NaCl + _H₃PO₄
The above equation can be balance as follow:
Na₃PO₄ + HCl —> NaCl + H₃PO₄
There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 3 before NaCl as shown below:
Na₃PO₄ + HCl —> 3NaCl + H₃PO₄
There are 3 atoms of Cl on the right side and 1 atom on the left side. It can be balance by writing 3 before HCl as shown below:
Na₃PO₄ + 3HCl —> 3NaCl + H₃PO₄
Now, the equation is balanced.
The coefficients are: 1, 3, 3, 1
Answer:
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Explanation:
Given data:
Energy of photon = 1.10 × 10⁻¹³ J.
Wavelength of photon = ?
Solution:
Formula:
E = h.c / λ
λ = h. c / E
λ = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.
λ = 19.878 × 10⁻²⁶m / 1.10 × 10⁻¹³ J
λ = 18.071 × 10⁻¹³ m
λ = 18.071 × 10⁻¹³ × 10⁹
λ = 18.071 × 10⁻⁴ nm
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
