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3 years ago

5

Please help me complete the following word equations:) also write the balanced equation, full ionic equation, and net ionic equa

tion. Also include the states:)
a) zinc nitrate + calcium sulphide—>

b) potassium + calcium chloride—>

1 answer:

AVprozaik [17]3 years ago

6 0

Explanation:

The states may differ depending on the reactions

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If 4.4 moles of al react, how many moles of h2so4 are consumed?

astraxan [27]

2 Al + 3 H₂SO₄ = Al₂(SO₄)₃ + 3 H₂

2 moles Al -------- 3 moles H₂SO₄
4.4 moles Al ------ ?

moles H₂SO₄ = 4.4 x 3 / 2

moles H₂SO₄ = 13.2 / 2

= 6.6 moles of H₂SO₄

hope this helps!

4 0

3 years ago

A solution was prepared by dissolving 195.0 g of KCl in 215 g of water. Calculate the mole fraction of KCl. (The formula weight

defon

Answer:

Approximately $0.180$ .

Explanation:

The mole fraction of a compound in a solution is:

$\displaystyle \frac{\text{Number of moles of compound in question}}{\text{Number of moles of all particles in the solution}}$ .

In this question, the mole fraction of $\rm KCl$ in this solution would be:

$\displaystyle X_\mathrm{KCl} = \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}$ .

This solution consist of only $\rm KCl$ and water (i.e., $\rm H_2O$ .) Hence:

$\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})}\end{aligned}$ .

From the question:

Mass of $\rm KCl$ : $m(\mathrm{KCl}) = 195.0\; \rm g$ .
Molar mass of $\rm KCl$ : $M(\mathrm{KCl}) = 74.6\; \rm g \cdot mol^{-1}$ .

Mass of $\rm H_2O$ : $m(\mathrm{H_2O}) = 215\; \rm g$ .
Molar mass of $\rm H_2O$ : $M(\mathrm{H_2O}) = 18.0\; \rm g\cdot mol^{-1}$ .

Apply the formula $\displaystyle n = \frac{m}{M}$ to find the number of moles of $\rm KCl$ and $\rm H_2O$ in this solution.

$\begin{aligned}n(\mathrm{KCl}) &= \frac{m(\mathrm{KCl})}{M(\mathrm{KCl})} \\ &= \frac{195.0\; \rm g}{74.6\; \rm g \cdot mol^{-1}} \approx 2.61\; \em \rm mol\end{aligned}$ .

$\begin{aligned}n(\mathrm{H_2O}) &= \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} \\ &= \frac{215\; \rm g}{18.0\; \rm g \cdot mol^{-1}} \approx 11.9\; \em \rm mol\end{aligned}$ .

The molar fraction of $\rm KCl$ in this solution would be:

$\begin{aligned} X_\mathrm{KCl} &= \frac{n(\mathrm{KCl})}{n(\text{All particles in this soluton})}\\ &= \frac{n(\mathrm{KCl})}{n(\mathrm{KCl}) + n(\mathrm{H_2O})} \\ &\approx \frac{2.61 \; \rm mol}{2.61\; \rm mol + 11.9\; \rm mol} \approx 0.180\end{aligned}$ .

(Rounded to three significant figures.)

8 0

3 years ago

How many moles of Magnesium Oxide are in 35g?

irga5000 [103]

Answer:

0.88mol

Explanation:

The number of moles, n, contained in a substance can be calculated using the formula;

Moles (n) = mass (m) ÷ molar mass (MM)

Molar mass of Magnesium oxide (MgO) = 24 + 16

= 40g/mol

According to the question, Mass of MgO = 35grams

Mole = 35/40

Mole = 0.875

Mole = 0.88mol

7 0

3 years ago

How many atoms are there in 2.0 moles of magnesium (Mg)?

hjlf

Answer:

It should be 1. 1.2 X 10^24

Explanation:

7 0

3 years ago

First to answer correctly gets brainleist

LenaWriter [7]

Answer:

c. Waxing crescent

- I hope this helps have a great night

3 0

3 years ago