2-(-x+5)
2+x-5
x-3
I decided to included the steps just in case you needed them
Part of the illustration is carved off.
Answer:
Step-by-step explanation:
<u>Given</u>
- Total 17 marbles
- 4 - blue marbles
- 6 - green marbles
- 2 - red marbles
- The rest - yellow marbles
<u>Probability of drawing red first:</u>
- P(red) = number of red / total number = 2/17
<u>Probability of drawing green second, without replacement:</u>
- P(green) = number of green / number left in the bag = 6/16 = 3/8
<u>Probability of red and green in order:</u>
- P = P(red)*P(green) = 2/17*3/8 = 3/68
It is given that getting boy or girl is equally likely. The chance of getting boy or girl on birth is 1/2
P(Boy) = P(Girl) =0.5
If a couple plans to have 8 children then probability of getting at least one girl is
P(Al least one girl out of 8 children) = 1 - P(No girl in 8 children)
= 1 - P( Getting all boys in 8 children)
= 1 - (0.5)^8
= 1 - 0.0039
P(At least one girl out of 8 children) = 0.9961
The probability of getting at least one girl out of 8 children is 0.9961.
The probability 0.9961 is high enough for the couple to be very confident that they will get at least one girl in 8 children
Answer:
D
Step-by-step explanation: