We have such equation
5x-3y=12 /-5x (subtract 5x both sides)
5x-5x-3y=12-5x
-3y=-5x+12 /:3 divide both sides by 3
-y= $\frac{-5x+12}{3}$ /*(-1) multiply both sides by -1
y=- $\frac{-5x+12}{3}$
y= $\frac{5x-12}{3}$ - its the answer

6 0

2 years ago

Solve for x.<br> 4x-7=19

SCORPION-xisa [38]

You add 7 to 19, so 26 and then divide it by 4.
X= 6.5

5 0

3 years ago

Read 2 more answers

I only need someone to put it in the quadratic formula I already have solutions. Please answer ASAP!!! I will give brainliest!!!

KengaRu [80]

The quadratic formula is $\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}$

and in the equation ax^2+bx+c=0

so now all you have to do is substitute the numbers into the quadratic formula

7 0

2 years ago

Solve for y<br> 2(3 + 3y) + y = 11

garik1379 [7]

<h2><u>EQUATION</u></h2><h3>Exercise</h3>

2(3 + 3y) + y = 11

First, apply the distributive property:

2(3 + 3y) + y = 11

6 + 6y + y = 11

6 + 7y = 11

Substract 6 from both sides:

6 - 6 + 7y = 11 - 6

7y = 5

Divide both sides by 7:

$\dfrac{7y}{7} = \dfrac{5}{7}$

$\boxed{y = \dfrac{5}{7}}$

<h3><u>Answer</u>. The value of y = 5/7.</h3>

8 0

2 years ago