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stich3 [128]
3 years ago
12

Margo can purchase tile at a store for $0.79 per tile and rent a tile saw for $24. At another store she can borrow the tile saw

for free if she buys tiles there for $1.19 per tile. How many tiles must she buy for the cost to be the same at both stores?
Mathematics
1 answer:
Monica [59]3 years ago
4 0
0.79 t + 24 =1.19t \\  \\ 1.19t - 0.79t =24 \\  \\ 0.4t =24 \\  \\ t =60 \\  \\  \\ \sf So, ~if~he~buys~60~tiles, ~then~the~price~will~be~the~same.
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Write the equation of the line that passes through the points (−4,1) and (−9,5). Put your answer in fully reduced point-slope fo
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Step-by-step explanation:

gradient(m)=change in y/change in x

=5-1/-9-(-4)

=4/-9+4

=4/-5

equation now

y-y1=m(x-x1)

y-1=4/-5[x-(-4)]

y=4/-5(x+4)+1

y=-4/5x-16/5+1

y=-4/5x-21/5

3 0
3 years ago
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A local department store sells carpet in 4 sizes. Each carpet comes in 3 different qualities. One of the sizes comes in 5 colors
e-lub [12.9K]

Answer:

23.

Step-by-step explanation:

You would multiply the 4 sizes of carpet by the 3 qualities, which equals 12. Then, you add 5+2+2+2. So it would end up being 12+11.

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3 years ago
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Answer:

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Step-by-step explanation:

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8090 [49]

Answer:

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Step-by-step explanation:

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3 years ago
Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer
Galina-37 [17]
According to the fundamental theorem of algebra, <span>every polynomial of degree n has n complex zeroes.

Part A:

Given

x(x^2-4)(x^2+16)=0 \\  \\ \Rightarrow x(x^4+12x^2-64)=0 \\  \\ \Rightarrow x^5+12x^3-64x=0

Thus, the given polynomial is of degree 5 and hence has 5 omplrex roots.



Part B:

Given

(x^2+4)(x+5)^2 = 0 \\  \\ \Rightarrow(x^2+4)(x^2+10x+25)=0 \\  \\ \Rightarrow x^4+10x^3+25x^2+4x^2+40x+100=0 \\  \\ \Rightarrow x^4+10x^3+29x^2+40x+100=0

Thus, the polynomial is of degree 4 and hence has 4 complex roots.



Part C:

Given

x^6-4x^5-24x^2+10x-3=0

Thus, the given polynomial is of degree 6 and hence has 6 complex roots.



Part D:

Given

x^7+128=0

</span><span>Thus, the given polynomial is of degree 7 and hence has 7 complex roots.</span>



Part E:

Given

(x^3+9)(x^2-4)=0 \\  \\ \Rightarrow x^5-4x^3+9x^2-36=0

Thus, the given polynomial is of degree 5 and hence has 5 complex roots.
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3 years ago
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