Since it is stated that it is an ideal gas, we use the ideal gas equation to solve the volume of this gas sample. The ideal gas equation is expressed as:
PV = nRT
V = nRT / P
V = 0.200 (8.314) (400) / 200x10^3
V = 3.33 x 10^-3 m³ or 3.33L
Therefore, the correct answer is option B.
2 <span>KOH +1 H3AsO4 →1 K2HAsO4 + 2 H2O</span>
Standard:560,000
Short form: 560 thousand
Word form: Five hundred six hundred thousand
Expanded form: 500,000+60,000
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Answer:
The temperature will decrease to 50 K
Explanation:
Step 1: Data given
Temperature = 127 °C = 400 K
Pressure = 2.00 atm
The pressure decreases to 0.25 atm
Volume and number of moles do not change
Step 2: Calculate the new pressure
p1/T1=p2/T2
⇒with p1 = The initial pressure = 2.00 atm
⇒with T1 = The initial temperature = 127 °C = 400 K
⇒with p2 = the new pressure = 0.25 atm
⇒with T2 = the new temperature = TO BE DETERMINED
2.00 atm / 400 K = 0.25 atm / T2
0.005 = 0.25 / T2
T2 = 0.25/0.005
T2 = 50 K
The temperature will decrease to 50 K