Question

What is the volume of 0.200 mol of an ideal gas at 200 kPa and 400 K? A. 0.83 L B. 3.33 L C. 5.60 L D. 20.8 L

Answer 1

The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2.
So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.
So under 200 kPa and 400 K is 3.33 L. So the answer is B.

Answer 2

Since it is stated that it is an ideal gas, we use the ideal gas equation to solve the volume of this gas sample. The ideal gas equation is expressed as:

PV = nRT
V = nRT / P
V = 0.200 (8.314) (400) / 200x10^3
V = 3.33 x 10^-3 m³ or 3.33L

Therefore, the correct answer is option B.