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Mandarinka [93]
3 years ago
12

What is the volume of 0.200 mol of an ideal gas at 200 kPa and 400 K? A. 0.83 L B. 3.33 L C. 5.60 L D. 20.8 L

Chemistry
2 answers:
timama [110]3 years ago
7 0
<span>The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2.
So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.
So under 200 kPa and 400 K is 3.33 L. So the answer is B.</span>
amid [387]3 years ago
3 0
Since it is stated that it is an ideal gas, we use the ideal gas equation to solve the volume of this gas sample. The ideal gas equation is expressed as:

PV = nRT
V = nRT / P
V = 0.200 (8.314) (400) / 200x10^3
V = 3.33 x 10^-3 m³ or 3.33L

Therefore, the correct answer is option B.
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How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
3 years ago
PLEASE HELP!! I have to pass this class! Anything!!
Georgia [21]

Answer:

We'll have 8.0 moles Fe3O4 and 4.0 moles CO2

Explanation:

Step 1: data given

Number of moles Fe2O3 = 12.0 moles

Number of moles CO = 12.0 moles

Step 2: The balanced equation

3Fe2O3 +CO → 2Fe3O4 + CO2

Step 3: Calculate the limiting reactant

For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2

Fe2O3 is the limiting reactant. It will completely be consumed (12.0 moles).

CO is in excess. There will react 12.0 / 3 = 4.0 moles

There will remain 12.0 - 4.0 = 8.0 moles

Step 4: Calculate moles products

For 3 moles Fe2O3 we need 1 mol CO to produce 2 moles Fe3O4 and 1 mol CO2

For 12.0 moles Fe2O3 we'll have 2/3 * 12.0 = 8.0 moles Fe3O4

For 12.0 moles Fe2O3 we'll have 12.0 / 3 = 4.0 moles CO2

We'll have 8.0 moles Fe3O4 and 4.0 moles CO2

6 0
3 years ago
Jane set up an experiment with 7 types of dog food and 15 dogs. Each day she fed a different brand of dog food to the 15 dogs. H
bixtya [17]

Answer:

I believe it's either D or A I did it in my math

4 0
3 years ago
Petroleum is a mixture of hydrocarbons. It is separated into useful fractions by fractional distillation.
Hunter-Best [27]

Explanation:

Fractional distillation is used to separate crude oil into simpler, more useful mixtures . This method can be used because different hydrocarbons have different boiling points

Hope this help u

3 0
3 years ago
Substances formed as the result of a reaction are called
kozerog [31]
The new substances that result from a chemical reaction is called product
6 0
3 years ago
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