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2 years ago

Acid and base ph PhET simulation lab

Chemistry

1 answer:

astra-53 [7]2 years ago

8 0

Answer:

Test the pH of things like coffee, spit, and soap to determine whether each is acidic, basic, or neutral. Visualize ... Investigate whether changing the volume or diluting with water affects the pH. ... Original Sim and Translations ... Lab, Chemistry.

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Answer:

The correct answer is:

d. Na2S, NaF

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3 years ago

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When co2 levels are low and o2 levels are high, rubisco adds an o2 molecule to rubp. what are the consequences of this reaction?

marissa [1.9K]

Rubisco is an important enzyme that helps in making lifeless carbon of carbon dioxide into organic molecules. Rubisco takes carbon dioxide and attaches it to ribulose bisphosphate, a short sugar chain with five carbon atoms that has rubp as its shortcut. Rubisco then clips the lengthened chain into to polyglycerate pices, which are pretty flexible molecules and are also used in the feeding of the plant. Most of it is used in the photosynthesis pathway, but some of it is used to make sucrose (table sugar) to feed the rest of the plant, or stored away in the form of starch for later use. Hence, rubisco is crucial in the storing of the energy that is created from photosynthesis.

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3 years ago

An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

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2 years ago

What type of energy is present in wound-up rubber band in a toy airplane?

andriy [413]

It is elastic potential energy

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3 years ago

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bagirrra123 [75]

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2 years ago