Answer:
<h2>
The no. of moles present in one liter solution is 0.843</h2>
Explanation:
Mass of ammonium chloride = 11.5 gm
Molar mass of ammonium chloride = 53.491 gm
No. of moles
N = 0.215 moles
M = 0.843 M
Thus the no. of moles present in one liter solution is 0.843
Answer:
8.28 MPa
Explanation:
From the question given above, the following data were obtained:
Radius (r) = 2×10¯³ m
Force applied (F) = 104 N
Pressure (P) =?
Next, we shall determine the area of the nail (i.e circle). This can be obtained as follow:
Radius (r) = 2×10¯³ m
Area (A) of circle =?
Pi (π) = 3.14
A = πr²
A = 3.14 × (2×10¯³)²
A = 3.14 × 4×10¯⁶
A = 1.256×10¯⁵ m²
Next, we shall determine the pressure. This can be obtained as follow:
Force applied (F) = 104 N
Area (A) = 1.256×10¯⁵ m²
Pressure (P) =?
P = F / A
P = 104 / 1.256×10¯⁵
P = 8280254.78 Nm¯²
Finally, we shall convert 8280254.78 Nm¯² to MPa. This can be obtained as follow:
1 Nm¯² = 1×10¯⁶ MPa
Therefore,
8280254.78 Nm¯² = 8280254.78 Nm¯² × 1×10¯⁶ MPa / 1 Nm¯²
8280254.78 Nm¯² = 8.28 MPa
Thus, the pressure exerted on the wall is 8.28 MPa
The rounding up of the aforementioned number to four significant figures is as follows: 3.002 × 10²
<h3>What are significant figures?</h3>
Significant figures are figures that contribute to the general and overall value of the whole number.
Significant figures or digits are specifically meaningful with respect to the precision of a measurement.
Although, the original number given in this question has 9 significant figures, the number; 300.235800 can be rounded up to four significant figures as follows:
- Decimal notation: 300.2
- No. of significant figures: 4
- No. of decimals: 1
- Scientific notation: 3.002 × 10²
Therefore, the rounding up of the aforementioned number to four significant figures is as follows: 3.002 × 10².
Learn more about significant figures at: brainly.com/question/14359464
#SPJ1
1.95 or 2 is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.
The correct answer is option b
Explanation:
Data given:
mass of KN
= 45.3 grams
volume = 0.225 litre
molarity =?
atomic mass of KNO3 = 101 grams/mole
molarity is calculated by using the formula:
molarity = 
first the number of moles present in the given mass is calculated as:
number of moles = 
number of moles = 
0.44 moles of KNO3
Putting the values in the equation of molarity:
molarity = 
molarity = 1.95
It can be taken as 2.
The molarity of the potassium nitrate solution is 2.
