Log_(10)(x² - 4x + 7) = 2
Take the base 10 anti log of both sides.
x² - 4x + 7 = 10² = 100
x²- 4x - 93 = 0
Quadratic Formula
x = [4 ± √(4²-4(1)(-93))]/[2(1)] = [4 ± 2√97)]/2 = 2 ± √97
Answer:
i did
Step-by-step explanation:
i already turned it in thoo
Step-by-step explanation:
I have solved the question it is in the picture I hope it helps
x = 8, --- 12
I hope this helped :))))))))))))))))))
Given:
Equation of line
.
To find:
The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.
Solution:
The given equation of line can be written as

Slope of line is



Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is


![[\because m_1=\dfrac{7}{4}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20m_1%3D%5Cdfrac%7B7%7D%7B4%7D%5D)
Now, the slope of perpendicular line is
and it goes through (-21,2). So, the equation of line is






Therefore, the required equation in slope intercept form is
.