Answer:
12 pounds
Step-by-step explanation:
We we need to write equations to represent the situation in this problem.
x=weight of package
UPS cost=6+1+0.15(x-2)
UPS cost=6+1+0.15x-0.3
UPS cost=6.7+0.15x
FedEx cost=4+2+.25(x-2)
FedEx cost=4+2+0.25x-0.5
FedEx cost=5.5+0.25x
Next, we can set the two equations equal to each other to solve for x.
6.7+0.15x=5.5+0.25x
6.7+0.15x-5.5=5.5+0.25x-5.5
1.2+0.15x-0.15x=0.25x-0.15x
1.2/0.1=0.1x/0.1
x=12
It takes 12 pounds for the UPS and FedEx packages to cost the same amount to ship.
7:5
8:15 days
Please don't get mad at me if their are incorrect but i'm sure they are right!
A prime number is such that it is divisible by only itself and one. ... Two is a prime because it is divisible by only two and one. All the other even numbers are not prime because they are all divisible by two. That leaves only the odd numbers.
<span>Hello, Yoloalanis. In order to solve this question that you have just posted, you only have to do a few simple steps. So, We can do this!</span>
<span />Let's start with your fraction. You will first have to change 9/12 into a decimal. In order to do this, you will have to divide the numerator by the denominator. A numerator is also known as the top part of the fraction. A denominator is the bottom part of the fraction. So, when you divide nine by twelve, you get 0.75 as a decimal. Now, you just have to multiply the decimal by 100 or to make it simpler, just move the decimal two places to the right. To sum it all up, you will get 75%.
Hope it helps :)
<h2>
Answer with explanation:</h2>
We know that a removable discontinuity occurs when:
The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.
Also it is a point on the graph such that it is undefined at that point.
The graph that has a removable discontinuity is attached to the answer.
Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.
