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STatiana [176]
3 years ago
11

If you toss 3 dices, what is the chance to get at least one 3?

Mathematics
2 answers:
Kitty [74]3 years ago
5 0

Answer: 0.4213

Step-by-step explanation:

For "at least" questions, it is useful to calculate the probability of that event not happening, In this case, the probability of not getting one three (or any specific number). It is quite obvious that for one dice you have a 5/6 chance of not getting a three. For three the probability of not getting a three would then be:

5/6⋅5/6⋅5/6=125/216=0.5787

So the opposite (getting at least one three) would be 1 minus that or 1 - 0.5787 = 0.4213

german3 years ago
3 0
Your chances are 91/216
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2 years ago
Find the output, d, when the input, t, is 11. <br><br><br> d = -20+11t<br><br> d= __
mafiozo [28]
Substitute the given value into the equation


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Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
miskamm [114]

Answer:

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Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

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_____

<em>Additional comment</em>

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