Point p is located in the first quadrant of a coordinate plane.If p is reflected across to form p',choose the four statements th
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Part A:
Given that t<span>he game of clue involves 6 suspects, 6 weapons, and 9 rooms.
The number of ways that one of each is randomly chosen is given by:
Therefore, the number of solutions possible is 324.
Part B:
Given that a </span>players is randomly given three of the remaining cards, <span>let s, w, and r be, respectively, the numbers of suspects, weapons, and rooms in the set of three cards given to a specified player.
The number of suspects, weapons, and rooms remaining respectively after the player observes his or her three cards are: 6 - s, 6 - w, and 9 - r.
Let x denote the number of solutions that are possible after that player observes his or her three cards, then:
Therefore, x in terms of s, w, and r is given by x = (6 - s)(6 - w)(9 - r).
Part C:
The expected value E(x) of a data set
with probabilities 
is given by 
There are </span>
possible combinations s, w and r. They are (3, 0, 0), (0, 3, 0), (0, 0, 3), (2, 1, 0), (0, 2, 1), (1, 0, 2), (2, 0, 1), (1, 2, 0), (0, 1, 2), (1, 1, 1)
Thus the expected value is given by
Given that t<span>he game of clue involves 6 suspects, 6 weapons, and 9 rooms.
The number of ways that one of each is randomly chosen is given by:
Therefore, the number of solutions possible is 324.
Part B:
Given that a </span>players is randomly given three of the remaining cards, <span>let s, w, and r be, respectively, the numbers of suspects, weapons, and rooms in the set of three cards given to a specified player.
The number of suspects, weapons, and rooms remaining respectively after the player observes his or her three cards are: 6 - s, 6 - w, and 9 - r.
Let x denote the number of solutions that are possible after that player observes his or her three cards, then:
Therefore, x in terms of s, w, and r is given by x = (6 - s)(6 - w)(9 - r).
Part C:
The expected value E(x) of a data set
There are </span>
Thus the expected value is given by
The proportion is 0.4401.
We find z-scores that correspond with both ends of this interval. Z-scores are given using the formula:
For the lower end,
The proportion of scores to the left of this number is 0.2514.
For the higher end, the z-score is
The proportion of scores to the left of this number is 0.6915.
To find just the proportion of scores between these two, we subtract;
0.6915-0.2514 = 0.4401.
We find z-scores that correspond with both ends of this interval. Z-scores are given using the formula:
For the lower end,
The proportion of scores to the left of this number is 0.2514.
For the higher end, the z-score is
The proportion of scores to the left of this number is 0.6915.
To find just the proportion of scores between these two, we subtract;
0.6915-0.2514 = 0.4401.