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agasfer [191]
4 years ago
12

Katie knew that 70 + 70 = 140. Explain how she can use this double to solve 70 + 89.

Mathematics
2 answers:
grigory [225]4 years ago
8 0
Just add 19 to 140.
White raven [17]4 years ago
6 0
She can use this double by first finding the different in between 70 and 89, which is 19. After finding that difference she should add 19 to the result of the double.
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What is the joint relative frequency for 11th graders who want the break in the afternoon? Round to the nearest percent.
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3 years ago
Help~~~~~~~~~~~~~~~~~~~~~~~~~
igor_vitrenko [27]

Answer:

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Step-by-step explanation:

A circumference of the circle is

C=2\pi r,

where r is the radius of the circle.

So,

18.84=2\pi r\\ \\r=\dfrac{18.84}{2\pi}=\dfrac{9.42}{\pi}\ cm

The area of the circle is

A=\pi r^2

Substitute the value of the radius:

A=\pi \cdot \left(\dfrac{9.42}{\pi}\right)^2=\dfrac{9.42^2}{\pi}\approx 28.25\ un^2

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3 years ago
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Which of these is the algebraic expression for "3 times the sum of 2 and y?"
11111nata11111 [884]
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8 0
3 years ago
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A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}

The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

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4 years ago
How to write 2.06 x 10 to the 10th power in standard form?
snow_tiger [21]

Answer:

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Step-by-step explanation:

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