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aleksandrvk [35]
3 years ago
15

Which gives the prices in order, from least to greatest unit rate? Price B, Price A, Price C Price C, Price B, Price A Price C,

Price A, Price B Price B, Price C, Price A
Mathematics
2 answers:
MArishka [77]3 years ago
7 0

Answer:

Price B, Price A, Price C

Step-by-step explanation:

Look at the table showing different prices for oranges.

Prices for Oranges

Price A

$2.25 for 6

Price B

$1.30 for 4

Price C

$0.97 for 2

Which gives the prices in order, from least to greatest unit rate?

Price B, Price A, Price C

Price C, Price B, Price A

Price C, Price A, Price B

Price B, Price C, Price A

Price A

$2.25 for 6

Price per orange = $2.25 / 6

= $0.375

Price B

$1.30 for 4

Price per orange = $1.30 / 4

= $0.325

Price C

$0.97 for 2

Price per orange = $0.97 / 2

= $0.485

From least to greatest unit rate

Price B , price A, price C

Law Incorporation [45]3 years ago
5 0

Ur answer is A, person on top of me is right

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Given the directrix of y = 6 and focus of (0, 4), which is the equation of the parabola?
krok68 [10]

y = \frac{1}{24} x^{2}

<u>Step-by-step explanation:</u>

Since directrix is a horizontal line, this is a regular vertical parabola, where the x part is squared.  The equation of a vertical parabola is:

(x - h)² = 4p(y - k)    

where,

(h,k) are the coordinates of the vertex

p = distance from the vertex to the focus

So, we need to find out h, k and p and plug those values :

We know that the vertex of a parabola is halfway between focus and the directrix . We know the focus (0,4) and directrix y = 6  therefore, vertex (h,k) = (0, 0)

Now, p = distance from the vertex to the focus

= distance from the (0,0) to the (0,4)

= 4

Plug all the values in equation:

(x-0)^{2} = 4(4)(y-0)\\x^{2} = 24y

Now, we rearrange to write this into standard form (y =ax^{2}+bx+c)

or,y = \frac{1}{24} x^{2}

7 0
3 years ago
Mia is helping her glee club raise money to fund a field trip. The glee club secided to sell pencils, which come in boxes of 100
Nitella [24]

Answer:

m = 2500b

Step-by-step explanation:

As instructed,

let b = number of boxes sold

let m = total money made.

The total money made, is a function of the number of boxes sold.

Let me break this down:

There are 100 pencils in a box;

if they sold only one box, they will get 100 X $25 = $2500;

if they sold two boxes, they will get 200 X $25 = $5000;

if they sold three boxes, they will get 300 X $25 = $7500;

Following the trend, we can deduce that money made, m = (number of boxes sold X 100 ) X $25

representing this using the variables we were given, we have

m = 100b X 25

hence

m = 2500b

7 0
3 years ago
Assume the sample variances to be continuous measurements. Find the probability that a random sample of 36 observations, from a
frez [133]

Answer:

0.02566

0.972559

Step-by-step explanation:

Given that :

Sample size (n) = 36

σ² = 6

sample variance S^2

a) greater than 9.1;

b) between 3.5 and 10.5.

The degree do freedom (df) = n - 1

S² > 9.1

P(S² > 9.1) = X² > ((n - 1) * S²) / 6

P(S² > 9.1) = ((36 - 1) * 9.1) / 6

P(S² > 9.1) = (35 * 9.1) / 6

P(S² > 9.1) = 53.083

P(X² > 53.08) = 0.02566 ( chi square distribution calculator)

b) between 3.5 and 10.5.

((36 - 1) * 3.5) / 6 ≤ S² ≤ ((36 - 1) * 10.5) / 6

20.416666 ≤ S² ≤ 61.25

Using the Chisquare distribution calculator :

P(X² > 20.42) = 0.9765

P(X² > 61.25) = 0.003941

Hence,

0.9765 - 0.003941 = 0.972559

7 0
3 years ago
D = rt ; Solve for t
Nastasia [14]

Answer:

T stands for time

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
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