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3 years ago

Number 1 ............

Chemistry

2 answers:

frutty [35]3 years ago

6 0

Answer:

I am guessing it is B. Non-metal, metals, metalloids

irga5000 [103]3 years ago

3 0

B. Metals, Non-Metals, Metalloids

Metals: located in the South and West of Periodic Table. Tend to give up electrons (form cations) and form simple ionic compounds with non-metal anions. Most of the 118 known elements are metals.

2. Non-Metals : located in the North and East of the Periodic Table. Tend to attract electrons (form anions) and combine with metal cations to make ionics, or share them with other non-metals and form covalent compounds . There are nineteen nonmetals, if we consider the ‘latest” two, which are not well characterized and have fleeting lifetimes.

3. Metalloids: straddle a staircase-like region between metals and non-metals. Their properties are intermediate between metals and non metals (in varying proportions). There are only seven metalloids.

So the answer is B ❤️

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Reptile [31]

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3 years ago

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Please solve! Thanks

WARRIOR [948]

Answer:

Oxygen needed for Stannous Oxide: 1.350g

Oxygen needed for Stannic Oxide: 2.710g

Explanation:

You're working with 10.00 grams of Tin mass for both Stannous Oxide and Stannic Oxide.

- 10.00 grams of Tin for Stannous Oxide is already 88.10% of the mass needed. You need to find how much 11.90% of Oxygen mass is needed to create the compound. Find a factor that you can multiply 88.10% by to get 100%

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- 10.00g * 1.135 = 11.35g (Tin + Oxygen)

- Subtract (Compound - Tin) to find Oxygen

- 11.35g - 10.00g = 1.350g (Oxygen)

Repeat the process with Stannic Oxide

- Find the factor that gets 78.70% to 100%

- 100/78.70 = 1.271

- Multiply by Tin mass

- 10.00g * 1.271 = 12.71g (Compound)

- Subtract Compound by Tin

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3 years ago

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3241004551 [841]

Answer:

819 K

Explanation:

Given data

Initial pressure (P₁): 1 atm (standard pressure)

Initial volume (V₁): 250 mL

Initial temperature (T₁): 273.15 K (standard temperature)

Final pressure (P₂): 0.500 atm

Final volume (V₂): 1500 mL

Final temperature (T₂): ?

We can find the final temperature using the combined gas law.

$\frac{P_1 \times V_1 }{T_1} = \frac{P_2 \times V_2 }{T_2}\\T_2 = \frac{P_2 \times V_2 \times T_1 }{P_1 \times V_1} = \frac{0.500atm \times 1500mL \times 273.15K }{1atm \times 250mL}=819K$

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denis-greek [22]

Answer:

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3 years ago

Number 1 ............​

Number 1 ............