Question

[urgent] What would the [OH-] of a solution that has a pOH of 2.7 be?

Answer 1

Answer:

[OH⁻] = 0.002 M

Explanation:

The definition of pOH is similar to the definition of pH:

• pOH = -log[OH⁻]

This means that with a given pOH value, the calculation of [OH⁻] is a matter of algebra:

• 2.7 = -log[OH⁻]

• -2.7 = log[OH⁻]

To remove the logarithm we increase 10 by the power of the pOH:

• $10^{-2.7}$=[OH⁻]

• 0.002 M = [OH⁻]