Question

Consider the equation below. CaCO3(s) <—>CaO(s) + CO2(g) what is the equilibrium constant expression for the given reaction?

Answer 1

Answer:

Answer is: Keq = [CO₂].

Explanation:

Balanced chemical reaction: CaCO3(s) ⇄ CaO(s) + CO₂(g).

The equilibrium constant (Keq) is a ratio of the concentration of the products  to the concentration of the reactants.

Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to  the equilibrium constant expression

Answer 2

Answer : The equilibrium constant expression for the given reaction is, $K_c=[CO_2]$

Explanation :

$K_c$ is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

$CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)$

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

The expression for equilibrium constant for this reaction will be,

$K_c=[CO_2]$

Therefore, the equilibrium constant expression for the given reaction is, $K_c=[CO_2]$