Answer:
B. CH₄
Explanation:
The primary rule in deciding solubilities is, Like dissolves like. That is,
- A polar solute dissolves in a polar solvent.
- A nonpolar solute dissolves in a nonpolar solvent.
C₆H₁₄ is a nonpolar solvent. Its strongest intermolecular forces are London dispersion forces.
CH₄ is a nonpolar solute. It contains only nonpolar C-H bonds, and its strongest intermolecular forces are London dispersion forces.
Molecules of the two compounds can easily intermingle with each other because the attractive forces between them are so small.
A is wrong. H₂O is a highly polar substance. Its molecules are so strongly attracted to each other that they will not dissolve in the C₆H₁₄.
C and D are wrong. Both NaCl and SnS are compounds of a metal and a nonmetal. We would predict them to be ionic solids, at the extreme end of polarity. They will not dissolve in C₆H₁₄.
The balanced chemical equations are as follows:
- AlBr₃ + K → 3 KBr + Al
- FeO + PdF₂ → FeF₂ + PdO
- P₄ + 6 Br₂ → 4 PBr₃
- 2 LiCl + Br₂ → 2 LiBr + Cl₂
<h3>What are balanced chemical equations?</h3>
Balanced chemical equations in which the moles of atoms of elements taking part in a reaction are balanced on both sides of the equation.
The balancing of chemical equations follows the law of conservation of mass which states that matter can neither be created nor destroyed.
In balancing of chemical equations, the following steps are follows:
- ensure that the all the substances involved are written in the equation
- do not alter the formula of compounds or molecules
- add numerical coefficients in front of the compounds and molecules to ensure that the moles of atoms of elements are balanced on both sides of the equation
In conclusion, a balanced chemical equation obeys the law of conservation of mass.
Learn more about balancing of chemical equations at: brainly.com/question/17056447
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Answer:
1. C- Three.
2. A- Methionine
3. D- Translocation.
4. C- OH.
5. A - 5'
6. A - 3' carbon
7. A. adenine and guanine
Explanation:
1. A codon is a group of three nucleotide sequence that encodes or specifies an amino acid. This means that, during translation (second stage of gene expression), when a CODON is read, an amino acid is added to the growing peptide chain.
2. The codon that initiates the translation process is called a start codon. It has a sequence: AUG and it specifies Methionine amino acid. Hence, during translation where a tRNA binds to the mRNA codon to read it and add its corresponding amino acid, a tRNA with a complementary sequence of AUG (start codon) binds to it and carries Methionine amino acid.
3. Translocation is a process during translation whereby the mRNA-tRNA moeity moves forward in the ribosome to allow another codon to move into the vacant site for translation process to continue.
4. The sugar component of a nucelotide that makes up the nucleic acid (DNA or RNA) i.e. ribose or deoxyribose, contains an hydroxyll functional group (-OH).
5. A nucleotide consists of a pentose (five carbon) sugar, phosphate group and a nitrogenous base. The phosphate group (PO43-) is attached to the 5' carbon of the sugar molecule.
6. The free hydroxyll group (-OH) of the five carbon sugar molecule in DNA is attached to its 3' carbon.
7. Nitrogenous bases are the third component of a nucleotide, the other two being pentose sugar and phosphate group. The nitrogenous bases are four viz: Adenine, Guanine, Cytosine, and Thymine. These bases are classified into Purines and Pyrimidines based on the similarity in their structure. Adenine (A) and Guanine (G) are Purines because they possess have two carbon-nitrogen rings, as opposed to one possessed by Pyrimidines (Thymine and Cytosine).
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