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navik [9.2K]
3 years ago
10

Find the sum of the first 5 terms of the infinite series: 8 + 18 + 28 +

Mathematics
2 answers:
PtichkaEL [24]3 years ago
4 0

Answer:

Step-by-step explanation:

140

Anna007 [38]3 years ago
3 0

Answer:

8 + 18+ 28+ 38+ 48= 140

Step-by-step explanation:

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The relation t relates x to y. To determine if it is a function, see if one x value can give two different y values. Since each x value only has one y value, the relation is a function. To check if the inverse is a function, see if any one y value will give multiple x values. By inversing t, there are two values of x for the value of y = -4 (x = 4 and x = 6), so this is NOT a function.

Answer: Relation t is a function. The inverse of relation t is NOT a function.
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50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
vazorg [7]

Hi there!

\large\boxed{35 \text{ units}^2}

Find the area of the parallelogram using the formula:

A = b × h

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HELP ME FIND THE ANGLE<br><br><br><br><br> HELP ME FIND ANGLE A
romanna [79]

Answer:

32 degrees

Step-by-step explanation: So they tell you BE is congruent to BC so triangle BCE is isosceles. We know that angle C is 35 degrees and the triangle is isosceles so angle E is 35 degrees too. Now we do 180-(35+35) and that equals 110 so angle B is 110. And we know that angle EBC and FBA are supplementary angles so 180-110 is 70 degrees so angle FBA is 70 degrees and you can do the same thing with angle DFB and AFB so 180-102 degrees is 78 degrees and to find angle a you just do 180-(70+78) and that equals 32 degrees so angle A is 32 degrees. :)

4 0
3 years ago
Find x for equation 10 points
alexgriva [62]

Hi!

3x - 30 = x + 10

<h3>Solve by isolating x on one side. </h3><h3>Add 30 to both sides. </h3>

3x - 30 + 30 = x + 10 + 30

3x = x + 40

<h3>Subtract x from both sides. </h3>

3x - x = x - x + 40

2x = 40

<h3>Divide by 2 on both sides</h3>

2x/2 = 40/2

<u>x = 20</u>

<h2>The answer is x = 20</h2>

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6 0
3 years ago
Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

\text{Minimum value }= 53

Q_1=62

Median=80

Q_3=86

\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

For second box plot

\text{Minimum value }= 56

Q_1=62

Median=74

Q_3=89

\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

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First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value.  It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range.  It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

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3 years ago
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