Answer:
5 pigs
Step-by-step explanation:
A farmhouse shelters 16 animals, some are pigs, and some are ducks. Altogether there are 42 legs. How many pigs are there?
Let us represent:
Number of pigs = x
Number of ducks = y
Our system of equations is given as:
A farmhouse shelters 16 animals, some are pigs, and some are ducks.
x + y = 16...... Equation 1
x = 16 - y
Altogether there are 42 legs.
Ducks have 2 legs(feet) , pigs have 4 legs,
4x + 2y = 42..... Equation 2
We substitute
16 - y for x in Equation 2
Hence:
4(16 - y) + 2y = 42
64 - 4y + 2y = 42
Collect like terms
- 4y + 2y = 42 - 64
-2y =- 22
y = -22/-2
y = 11 ducks
Solving for x.
x = 16 - y
x = 16 - 11
x = 5 pigs
Therefore, we have 5 pigs
Answer: C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)
Step-by-step explanation:
The data set is:
(9, 22)
(10,32)
(11, 41)
(12, 30).
In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).
Then the domain would be:
{9, 10, 11, 12}
and the range:
{22, 32, 41, 30}
The correct option is C
Answer:
D
Step-by-step explanation:
I'm not the greatest in this subject, but I think that it's D/If the roof leaks, then the ceiling gets damaged because it clearly says that in the statement. It could be all of them, though, but this is my answer. Hope it helps!
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
