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3 years ago

Could someone help me figure this out??

Mathematics

1 answer:

irinina [24]3 years ago

6 0

Answer:

180

Step-by-step explanation:

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ravis gas tank is 1/2 full .after he buys 2 gallons of gas it is 2/3 full how many gallons can ravis tank hold?

aliya0001 [1]

So
1/2x+2=2/3x
convert to common fraction
1/2=3/6
2/3=4/6
3/6x+2=4/6x
subtract 3/6x from both sides
2=1/6x
multiply boh tisdes by 6
12=x
the tank can hold 12 gallon

8 0

3 years ago

What are the mean, median, and mode of members in these K-Pop groups? <br> 7, 9, 5, 7, 7, 13, 18

Aloiza [94]

mean=the average of the numbers calculated. median=the number in the middle. mode=the numbers that appear most often

6 0

4 years ago

Can someone help me with this two because I am very confused

Tasya [4]

Answer:

Let the height of the larger box = h

and length and width of the larger box = l and w , repectively

Now , Let find the volume of the larger box

Volume = length * width * height

So Volume of the larger box = l*w*h = lwh

Now the question says

the height of the smaller box is 80% of the height of the larger box

It means

Height of the smaller box = 80% of h = 0.80*h = 0.80h

and the other two dimensions are same so it means length and width of the smaller box = l and w

so, Volume of the smaller box = l*w*0.80h = 0.80lwh

So the Difference in the volume of the two boxes = Volume of larger box - Volume of smaller box

therefore , Difference in the Volume of two boxes = lwh - 0.80 lwh = 0.20lwh

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Where is 23/2 on a number line?

rodikova [14]

23/2 = 11 1/2 or 11.5....its gonna be midway between 11 and 12 on a number line.

6 0

3 years ago

What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract

fgiga [73]

Answer:

$|z| = 27$ -- Modulus

$\theta = \frac{\pi}{3}$ --- Argument

Step-by-step explanation:

Given

$((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Required

Determine the modulus and the argument

We have that:

$z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Expand:

$z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

A complex equation can be expressed as:

$z = |z| e^{i\theta}$

Where

$|z| = modulus$

$\theta = argument$

Where

$e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})$

So:

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$ becomes

$z = 27(e^{i\frac{\pi}{18}})^6$

By comparison:

$e^{i\theta} = (e^{i\frac{\pi}{18}})^6$

This gives:

${i\theta} = i\frac{\pi}{18}}*6$

${i\theta} = i\frac{6\pi}{18}}$

${i\theta} = i\frac{\pi}{3}}$

Divide through by i

$\theta = \frac{\pi}{3}$

Hence, the modulus, z is:

$|z| = 27$

And the argument $\theta$ is

$\theta = \frac{\pi}{3}$

4 0

3 years ago