Answer:
The factorized form of the given expression is ![4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]](https://tex.z-dn.net/?f=4%20%5B%28a-1%29%5E2%20-%20b%28a%20-%201%20%2B%20%5Cfrac%7Bb%7D%7B4%7D%29%5D)
Step-by-step explanation:
Given;
4a² + b² - 4ab - 8a + 4b + 4
This expression is factorized as follows;
(4a² - 8a + 4) + (b² - 4ab + 4b)
(4a² - 4a - 4a + 4) + b² - 4b(a - 1)
(4a - 4)(a - 1) + b² - 4b(a - 1)
(4a - 4)(a - 1) - 4b(a - 1) + b²
4(a - 1)(a - 1) - 4b(a - 1) + b²
4(a - 1)² - 4b(a - 1 + b/4)
![4(a- 1)^2 - 4b(a - 1 + \frac{b}{4} )\\\\4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]](https://tex.z-dn.net/?f=4%28a-%201%29%5E2%20-%204b%28a%20-%201%20%2B%20%5Cfrac%7Bb%7D%7B4%7D%20%29%5C%5C%5C%5C4%20%5B%28a-1%29%5E2%20-%20b%28a%20-%201%20%2B%20%5Cfrac%7Bb%7D%7B4%7D%29%5D)
an example that opposes or contradicts an idea or theory.
Hello from MrBillDoesMath
Answer:
[email protected] = - sqrt(7)/ 4
which is choice B
Discussion:
This problem can be solved by drawing triangles and looking at ratios of sides or by using the trig identity:
([email protected])^2 + (sin2)^2 = 1
If [email protected] = 3/4
, the
([email protected])^2 + (3/4)^2 = 1 => (subtract (3/4)^2 from both sides)
([email protected])^2 = 1 - (3/4)^2 = 1 - 9/16 = 7/16
So...... taking the square root of both sides gives
[email protected] = +\- sqrt(7)/ sqrt(16) = +\- sqrt(7)/4
But is [email protected] positive or negative? We are told that @ is in the second quadrant and cos(@) is negative in this quadrant, so our answer must be negative
[email protected] = - sqrt(7)/ 4
which is choice B
Thank you,
Mr. B
50%. If you divide 28 by 14, (14/28), you’d get 0.5. Move the decimal place two places to the right, and that’s 50% :)
When I do what the problem statement says, I get 47° for the left angle and 58° for the right one. They are not congruent.
