Answer:
Option A) independent variable – self-affirmations; dependent variable – self-esteem scores
Step-by-step explanation:
We are given the following in the question:
"Wood and colleagues (2009) examined the value of self-affirmation. In a typical study, participants either engaged or did not engage in self-affirmations. Later, their current self-esteem was assessed."
Independent and Dependent Variable:
- Dependent variable is the variable whose value depends on the independent variable.
- Independent variable is the free variable.
For the given scenario, self esteem is assessed based on the fact that participants either engaged or did not engage in self-affirmations.
Thus, the dependent variable is self esteem and the independent variable is engagement in self affirmation.
Thus, the correct answer is
Option A) independent variable – self-affirmations; dependent variable – self-esteem scores
Answer:
Step-by-step explanation:
For , we have two cases:
Therefore, for , we have the following cases:
Solving, we have:
.
Therefore,
Answer:
46.5
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.
Given y = f(x) then f(x + a) is a horizontal translation of a units
• If a > 0 then shift to the left of a units
• If a < 0 then shift to the right of a units
Here shift to the right of 1 unit, thus
y = f(x - 1)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note the y- coordinates are the negative of each other, thus
- y = f(x)
Now = - y, hence
The equation for the red graph is
= f(x - 1) → C
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Answer:
y =
Step-by-step explanation:
First, we need to rearrange the equation to make it y = mx + c
4x - y = 3
y + 3 = 4x
y = 4x -3
So the slope of the line is 4.
The slope of a line perpendicular to an equation is:
So the slope of the perpendicular line is:
= -0.25
Now to find the equation of a line you can use the following equation:
y - y₁ = m(x - x₁)
Where y₁ is the y-coordinate, x₁ is the x-coordinate and m is the gradient. Plug the values in:
y₁ = 6
x₁ = -5
m =
y - 6 = (x - - 5)
To get rid of the fraction we need to multiply the whole equation by 4:
4y - 24 = -1(x - - 5)
The two negatives cancel out:
4y - 24 = -1(x + 5)
Multiply the brackets out:
4y - 24 = -x + 5
Now, to rearrange the formula back into y = mx + c
Move the -24 over to the other side making it a +24:
4y = 2x + 5 + 24
4y = 2x + 29
Divide everything by 4:
y =
y =
<h2>Hope this helps!</h2>