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nydimaria [60]
3 years ago
10

answer correctly for 70 points but if rong i will report u and get all ur points and mine back and u banned

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

11) 0.6

12) The maximum height of the ball was 2[ seconds] after it was thrown (I am assuming because the answers are cut off a bit.)

13) $2.50

14) (2,-15)

15) I don't know, since I can't see all the graphs and options. But I want to say the sideways parabola, or the only one shown in the image given

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Find the slope of the line graphed below.
Law Incorporation [45]

Answer:

8/5

Step-by-step explanation:

7 0
3 years ago
What is 20% of 55?<br> I need help PLEASE!
Assoli18 [71]
20% of 55 is 11

Convert your percentage into a decimal: 
\frac{20}{100} = 0.2

Multiply your decimal by 55:
0.2 \times 55 = 11
8 0
3 years ago
Read 2 more answers
Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam
MariettaO [177]
  • X-(A\cup B)=(X-A)\cap(X-B)

I'll assume the usual definition of set difference, X-A=\{x\in X,x\not\in A\}.

Let x\in X-(A\cup B). Then x\in X and x\not\in(A\cup B). If x\not\in(A\cup B), then x\not\in A and x\not\in B. This means x\in X,x\not\in A and x\in X,x\not\in B, so it follows that x\in(X-A)\cap(X-B). Hence X-(A\cup B)\subset(X-A)\cap(X-B).

Now let x\in(X-A)\cap(X-B). Then x\in X-A and x\in X-B. By definition of set difference, x\in X,x\not\in A and x\in X,x\not\in B. Since x\not A,x\not\in B, we have x\not\in(A\cup B), and so x\in X-(A\cup B). Hence (X-A)\cap(X-B)\subset X-(A\cup B).

The two sets are subsets of one another, so they must be equal.

  • X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices i\in I.

Proof of one direction for example:

Let x\in X-\left(\bigcup\limits_{i\in I}A_i\right). Then x\in X and x\not\in\bigcup\limits_{i\in I}A_i, which in turn means x\not\in A_i for all i\in I. This means x\in X,x\not\in A_{i_1}, and x\in X,x\not\in A_{i_2}, and so on, where \{i_1,i_2,\ldots\}\subset I, for all i\in I. This means x\in X-A_{i_1}, and x\in X-A_{i_2}, and so on, so x\in\bigcap\limits_{i\in I}(X-A_i). Hence X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i).

4 0
3 years ago
It is given that quadrilateral ABCD is a kite. We know
NemiM [27]

Answer:

Kite

Perpendicular

Reflexive

HL

Step-by-step explanation: Just did it on edg 2021.

3 0
3 years ago
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K=d d=5 find k<br><br><br> Determine the value of the indicated variable
svet-max [94.6K]
K=d
d=5

Since K is equal to d, and d is 5, the value of K is 5.

K=5
5(K)=5(d)
4 0
3 years ago
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