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3 years ago

A kangaroo hops 2 kilometers in 3 minutes at this rate how far does the kangaroo travel in 2 minutes

Mathematics

2 answers:

exis [7]3 years ago

7 0

Answer:

2 1/2 or 2 and a half

Step-by-step explanation:

if you divide it it will come out to be that (I hope its right but i don't know if it is

LenaWriter [7]3 years ago

6 0

Answer to this question: "A kangaroo hops 2 kilometers in 3 minutes at this rate how far does the kangaroo travel in 2 minutes"

2.50

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Solve the inequality

Lana71 [14]

3x-12>15
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4 years ago

Two quadratic functions are shown.

slava [35]

Answer:

Option (1) is the correct option.

Step-by-step explanation:

Function 1,

f(x) = 4x² + 8x + 1

= 4(x² + 2x) + 1

= 4(x² + 2x + 1 - 1) + 1

= 4(x² + 2x + 1) - 4 + 1

f(x) = 4(x + 1)² - 3

This graph opens up with the vertex or minimum point at (-1, -3)

So, the minimum value of the function is (-3) at x = -1.

Function (2)

From the given table minimum value of the function is 0 at x = -1 or minimum point as (-1, 0)

Therefore, Function 1 has the least minimum value and its coordinates are (-1, -3)

Option (1) is the correct option.

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3 years ago

ANSWER !! <br> ILL GIVE 40 POINTS !!<br> DONT SKIP :(( <br> PLUS BRAINLIEST !

Likurg_2 [28]

Answer:

Step-by-step explanation:

10x13=130, 9x5=45, 130-45=85

4 0

3 years ago

The table below shows some inputs and outputs of the invertible function f etc

Snowcat [4.5K]

Answer:

$(a)\ f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)=0$

Step-by-step explanation:

Given

The attached table

$(a)\ f^{-1}(-15)$

This represents an inverse function.

So, we look into x row for its value.

i.e.

$f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)$

Just like (a)

$f^{-1}(4) = -11$ ---- by looking into the x rows

$f(9) = 11$

So:

$f^{-1}(4) + f(9)=-11 + 11$

$f^{-1}(4) + f(9)=0$

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3 years ago

What is the average rate of change of the function f(x)=20(14)xf(x)=20(14)x from x = 1 to x = 2? Enter your answer, as a decimal

Advocard [28]

The average rate of a function f(x) over an interval x = a and x = b is given by:

$Average \ Rate \ of \ Change= \frac{f(b)-f(a)}{b-a}$

Given the function

$f(x)=20(14)^x$

The average rate of change from x = 1 to x = 2 is given by:

$\frac{f(2)-f(1)}{2-1} = \frac{20(14)^2-20(14)^1}{1} \\ \\ =20(196-14)=20(182)=3,640$

6 0

4 years ago