The answer to the equation is X= 27
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
You just take the number of the color of interest (green) and divide by total marbles
9/35 = 0.257 ~~ 25.7%
Answer:
σ should be adjusted at 0.5.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean 12.
Assuming we can precisely adjust σ, what should we set σtobe so that the actual amount dispensed is between 11 and 13 ounces, 95% of the time?
13 should be 2 standard deviations above the mean of 12, and 11 should be two standard deviations below the mean.
So 1 should be worth two standard deviations. Then
σ should be adjusted at 0.5.
Answer:
slope of a line m : 0
Equation of line : y=- 9
Step-by-step explanation:
P1 : (X1 , Y1 ) (-3 , -9)
P2 : (X2 , Y2) (5 , -9)
Slope of line (m) is caculated as ,
m = ( y2-y1)/(x2 - x1)
m = (-9 - (-9))/(5 - (-3))
m = 0
equation of line : y = mx+b
using P1 (-3 , -9)
= > (-9) = (0)(-3) + b
= > -9 = b
hence b = -9
equation of Line is
y = -9
