Ask question

Ask question

All categories

2 years ago

10

Some one help me please

1 answer:

levacccp [35]2 years ago

7 0

I think the answer is 6t=9

You might be interested in

Jimmy is trying to factor the quadratic equation $ax^2 + bx + c = 0.$ He assumes that it will factor in the form \[ax^2 + bx + c

Shkiper50 [21]

If

$ax^2+bx+c=(Ax+B)(Cx+D)$

then

$ax^2+bx+c=ACx^2+(AD+BC)x+BD$

$\implies a=AC$

If $a$ is known and Jimmy wants to find $A$ , then he has to know the value of $C$ .

6 0

2 years ago

Read 2 more answers

2x³-8=0<br> How do I solve this problem ?

wlad13 [49]

Answer:

$x=2^{\frac{2}{3}}$

Step-by-step explanation:

1) Add 8 to both sides.

<em /> $2x^3=8$

2) Divide both sides by 2.

$x^3=\frac{8}{2}$

3) Simplify $\frac{8}{2}$ to 4.

$x^3=4$

4) Take the cube root of both sides.

$x=\sqrt[3]{4}$

5) Rewrite 4 as 2².

$x=\sqrt[3]{2^2}$

6) Use this rule: ${({x}^{a})}^{b}={x}^{ab}$ .

$x=2^{\frac{2}{3}}$

Decimal Form: 1.587401

__________________________________________

Check the answer:

$2x^3-8=0$

1) Let $x=2^\frac{2}{3}$ .

$2(2^{\frac{2}{3} })-8=0$

2) Use this rule: $(x^a)^b=x^{ab}$ .

$2\times2^{\frac{2\times3}{3} } -8=0$

3) Simplify 2 * 3 to 6.

$2\times2^{\frac{6}{3} } - 8 =0$

4) Simplify 6/3 to 2.

$2\times2^2-8=0$

5) Use Product Rule: $x^ax^b=x^{a+b}$ .

$2^3-8=0$

6) Simplify 2^3 to 8.

8 - 8 = 0

7) Simplify 8 - 8 to 0.

0 = 0

Thank you,

Eddie

5 0

1 year ago

URGENT PLEASE HELP!!!

Naily [24]

15.7 feet
and you are welcome

7 0

3 years ago

Read 2 more answers

HELLPP PLZ <br> Plzzzzzzzz

irina [24]

Answer:

i need a better veiw

Step-by-step explanation:

3 0

2 years ago

Telephone inquiries of 100 IRS "customers" are monitored daily at random. Incidents of incorrect information or other nonconform

oee [108]

such huge question but tuff so sorry

5 0

3 years ago