Some one help me please

Which choice is equivalent to the product below?

Igoryamba

The answer should be
C

7 0

3 years ago

What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)? (0,0) (0,4) (–4,0) (2,0)

forsale [732]

Answer:

The midpoint of the x-intercepts of the function is (0, 0)

Step-by-step explanation:

Notice that since the function comes in factor form, we know that its roots (which are actually the intercepts the function has with the x-axis) are: x = 4 and x = -4 (the x-values for which the function renders zero).

These two points are equidistant from the origin of coordinates (0, 0), and therefore the midpoint of these x-intercepts is (0, 0).

6 0

3 years ago

Ok y’all help ʜᴇʟᴘᴘᴘᴘᴘ ndjd d dndkdjdjdkdnfn dkcn

umka21 [38]

Answer:

C, 108 ft²

Step-by-step explanation:

To solve, we need to find the area of each of the shapes and then add them together.

The top rectangle's area: 8 * 3 = 24

The left triangle: 3 * 4 * 0.5 = 6

The middle rectangle: 8 * 4 = 32

The right triangle: 4 * 3 * 0.5 = 6

The bottom rectangle: 5 * 8 = 40

Add them all together.

24 + 6 + 32 + 6 + 40 = 108 ft²

Thus, the answer is C, 108 ft²

8 0

3 years ago

Read 2 more answers

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

3 years ago

Cual es la respuesta de la imagen adjunta

FrozenT [24]

Answer:

b

Step-by-step explanation:

5 0

3 years ago