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3 years ago

A gardener is planting two types of trees:

Mathematics

1 answer:

denpristay [2]3 years ago

7 0

It takes 12 years for both trees to be of same height

Solution:

Assume the year that it would take to these trees have the same height is : x (years)

Type A is 7 feet tall and grows at a rate of 23 inches per year:

Convert 7 feet to inches

We know that,

1 foot = 12 inch

7 feet = 12 x 7 inch = 84 inch

Thus, type A is 84 inches tall and grows at a rate of 23 inches per year

We can frame a equation as:

Type A = 84 + 23(number of years)

Type A = 84 + 23x ---------- eqn 1

Type B is 5 feet tall and grows at a rate of 25 inches per year

Convert 5 feet to inches

5 feet = 5 x 12 inches = 60 inches

Thus, type B is 60 inches tall and grows at a rate of 25 inches per year

We can frame a equation as:

Type B = 60 + 25(number of years)

Type B = 60 + 25x --------- eqn 2

For both the trees to be of same height, eqn 1 must be equal to eqn 2

84 + 23x = 60 + 25x

25x - 23x = 84 - 60

2x = 24

x = 12

Thus it takes 12 years for both trees to be of same height

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Answer:

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Step-by-step explanation:

Divide the y values (games played) by the x values (games won) to find your ratio. The ratio across each of these pairs is 1.666667...

Using the ratio provided, 18:30, divide 30 by 18.

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3 years ago

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Step-by-step explanation:

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3 years ago

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My Homework Mr Thompson please help!!

Nady [450]

Answers:

C) Factored form
C) Standard form
D) The y intercept is -8
B) Two solutions: x = -5 or x = 5
B) Apply square root to both sides

=========================================

Explanations:

For problems 1 and 2, there's not much to say other than you'll just have to memorize those terms. Standard form is ax^2+bx+c in general. The exponents count down 2,1,0. Factored form is where we have two or more factors multiplying with each other. Think of something like 21 = 7*3 showing that 7 and 3 are factors of 21.
For problem 3, the y intercept is the last value. It's the constant value. Plug in x = 0 and you'll get y = -8 as a result. The y intercept always occurs when x = 0.
In problem 4, we apply the square root to both sides to get x = -5 or x = 5. The plus or minus is needed. This is because (-5)^2 = 25.
In problem 5, we apply the square root to both sides to undo the squaring operation.

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3 years ago

Simplify the square root of 2 times the cube root of 2.

aev [14]

Answer:

two to the five sixths power

Step-by-step explanation:

$\sqrt{2} *\sqrt[3]{2} =2^{\frac{1}{2} }*2^{\frac{1}{3} } = 2^{\frac{1}{2} +\frac{1}{3}}=\\=2^{\frac{5}{6} }$

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3 years ago

henry has 68 miles to destination after 45 minutes and 51.5 miles to destination after 71 minutes of driving. How many miles to

Airida [17]

Let d represent the distance of the destination from the starting point.

After 45 min, Henry has already driven d-68 miles. After 71 min., he has already driven d-51.5 miles.

So we have 2 points on a straight line:

(45,d-68) and (71,d-51.5). Let's find the slope of the line thru these 2 points:

d-51.5 - (d-68) 16.5 miles
slope of line = m = ----------------------- = ------------------
71 - 45 26 min

Thus, the slope, m, is m = 0.635 miles/min

The distance to his destination would be d - (0.635 miles/min)(79 min), or

d - 50.135 miles. We don't know how far his destination is from his starting point, so represent that by "d."

After 45 minutes: Henry has d - 68 miles to go;

After 71 minutes, he has d - 51.5 miles to go; and

After 79 minutes, he has d - x miles to go. We need to find x.

Actually, much of this is unnecessary. Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is

(0.635 miles/min)(8 min) = 5.08 miles. Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.

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3 years ago