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EastWind [94]
3 years ago
13

State whether each pair of triangles is similar by AA-SSS-or SAS-. If none of

Mathematics
1 answer:
alexgriva [62]3 years ago
3 0
It doesn’t tell me what to put
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Hi please i nedd help with these questions .
Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}

division sign means that we flip the fraction

\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}

now we can multiply all the constants together and all variables

m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}

now we can combine all the parts

\frac{3u^3v}{16m^2}

#2:

\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}

\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}

a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18

\frac{18b^3}{c^4}

3 0
3 years ago
Read 2 more answers
Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?
neonofarm [45]
\text{The formula of a slope:}\ m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{We have:}\\C(3;\ -5)\to x_1=3;\ y_1=-5\\D(6;\ 0)\to x_2=6;\ y_2=0\\\\\text{substitute}\\\\m=\dfrac{0-(-5)}{6-3}=\dfrac{5}{3}\\\\\text{The point-slope formula:}\ y-y_1=m(x-x_1)\\\\\text{substitute}\\\\y-(-5)=\dfrac{5}{3}(x-3)\\\\y+5=\dfrac{5}{3}x-5\ \ \ |-5\\\\\boxed{y=\dfrac{5}{3}x-10}
3 0
3 years ago
Read 2 more answers
I need help with 1 2 3
g100num [7]
D D B I think this should be right
7 0
3 years ago
Jaxon is creating a mosaic design on a rectangular
olasank [31]

Answer:

hard question

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find two numbers, if their sum is −11 and their difference is 41
snow_tiger [21]

The larger one is (-11 + 41)/2 = 15.

The smaller one is (-11 -41)/2 = -26.

_____

For two numbers a and b with sum s and difference d, you can write the equations

a+b=s\\a-b=d

Then adding the equations and dividing that sum by 2, you get

(a+b)+(a-b)=(s)+(d)\\2a=s+d\\a=\dfrac{s+d}{2}

You can subtract the second eqution from the first and get a similar result for the smaller number

(a+b)-(a-b)=(s)-(d)\\2b=s-d\\b=\dfrac{s-d}{2}

These are the formulas we used above.

3 0
4 years ago
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