Let total amount spent =x
Dita spent 35 % of total amount.
35% of x = 0.35x
So amount spent by Dita = 0.35x
% of money spent by Benton = 20 % of x = 0.2x
We are given that Benton spent $12 more than Claire,
so making equation we have ,
Money spent by Dita = Money spent by Claire +12
![0.35x =0.2x +12](https://tex.z-dn.net/?f=%200.35x%20%3D0.2x%20%2B12%20)
![0.35x -0.2x = 12](https://tex.z-dn.net/?f=%200.35x%20-0.2x%20%3D%2012%20)
![0.5x =12](https://tex.z-dn.net/?f=%200.5x%20%3D12%20)
x=80
So total amount spent was $80.
Money spent by Benton = 0.2x = 0.2 * 80= $16
So amount spent by Benton is $16.
So firstly, multiply both sides by 4 (the reciprocal of 1/4): ![x+2=\frac{20}{6}=3\frac{2}{6}](https://tex.z-dn.net/?f=%20x%2B2%3D%5Cfrac%7B20%7D%7B6%7D%3D3%5Cfrac%7B2%7D%7B6%7D%20)
Next, subtract both sides by 2 and your answer will be: ![x=1\frac{2}{6}](https://tex.z-dn.net/?f=%20x%3D1%5Cfrac%7B2%7D%7B6%7D%20)
42
It’s 42 since if you would convert this
Answer:
$8.50
Step-by-step explanation:
I don't know what Alls are, but if Carlos insists, we can calculate how much he can spend on Alls with the expression:
($31.50) + r
$40
This says the sum of what Carlos has already spent (hot dogs and hamburgers) plus the amount he spends on Alls (rolls?), r, must be equal to or less than the $40 he has allowed himself to spend.
($31.50) + r
$40
r
$40 - $31.50
r
$8.50